Java从XML文件获取属性并创建对象

Question

I have a xml file like this:

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<ActionDictionary>
    <action id="100000">
        <actiontype>BackupFile</actiontype>
        <filename>translated.properties</filename>
    </action>

    <action id="100001">
        <actiontype>ModifyPropertiesFile</actiontype>
        <filename>translated.properties</filename>
    </action>


    <action id="100002">
        <actiontype>DeployDomain</actiontype>
        <hostname>localhost</hostname>
        <port>8000</port>
        <domainhome>c:\\domain</domainhome>
    </action>   
</ActionDictionary> 

When executing, an action id will be give to the program (ex: id="10000"). The program will use the id to get all properties of the action tag in the xml file above which have the same id with the given id. These properties could be put to somewhere like an object. Then I could use this object to continue the other business.

How could I implement this in Java?

Answer 1

@Hoang, you can use javax.xml.bind.annotation.XmlElement and javax.xml.bind.annotation.XmlType of Javax api.

I would suggest to have a read through api docs Javax API