[英]Regex - Match from Character to Character only if a specified String is in between the Group
I want to match the string between two ")" characters only if a specified word is found in the string. 我只想在字符串中找到指定的单词时才匹配两个“)”字符之间的字符串。
For example, consider this block of text: 例如,考虑以下文本块:
...Milwaukee 2 (FINAL) Arizona 6 Chicago Cubs 5 (BOT 6TH) NY Mets 4 Colorado 5 (FINAL) Detroit...
with the specified word being "Colorado". 指定的单词是“科罗拉多”。 The language being used is Kustom, but for simplicity, consider the language to be javascript with lookbehinds. 所使用的语言是Kustom,但为简单起见,请将该语言视为带有lookbehinds的javascript。
I would like to match: 我想搭配:
NY Mets 4 Colorado 5 (FINAL)
I tried: (?<=\\)).*?(Colorado).*?(?:\\))
but it returns a match starting from the first ")" to the one after Colorado. 我试过: (?<=\\)).*?(Colorado).*?(?:\\))
但它返回的匹配项是从第一个“)”到科罗拉多州之后的那个。
Staring from a word boundary this captures: 从单词边界开始,它捕获:
the closing bracket 结束括号
\\b[\\w\\s]*?Colorado[\\w\\s\\(]*?\\)
try this (?!\\s).*?Colorado.*?(?:\\))
试试这个(?!\\s).*?Colorado.*?(?:\\))
s = `...Milwaukee 2 (FINAL) Arizona 6 Chicago Cubs 5 (BOT 6TH) NY Mets 4 Colorado 5 (FINAL) Detroit...` m = s.match(/(?!\\s).*?Colorado.*?(?:\\))/gm) console.log(m[0]);
` `
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