[英]TimeDelta to generate Pandas Index
I am working with intraday stock data that i have downloaded to a CSV file. 我正在处理已下载到CSV文件的当日股票数据。 The data contains the stock price for MO per minute.
数据包含每分钟MO的股票价格。 In order to generate a time-frame for the data, i use the pandas function:
为了生成数据的时间范围,我使用了pandas函数:
pd.timedelta_range('1 days 9 hours 30 minutes', periods=len(df), freq='min')
pd.timedelta_range('1天9小时30分钟',期间= len(df),频率='分钟')
To add the two dataframes togehter, i use the following 为了将两个数据帧加在一起,我使用以下内容
time = pd.DataFrame(data = df,index=pd.timedelta_range('1 days 9 hours 30 minutes', periods=len(df), freq='min'))
time = pd.DataFrame(data = df,index = pd.timedelta_range('1 days 9 hours 30 minutes',period = len(df),freq ='min'))
It results in this 结果是这样
MO
1 days 09:30:00 NaN
1 days 09:31:00 NaN
1 days 09:32:00 NaN
1 days 09:33:00 NaN
1 days 09:34:00 NaN
Not sure why i am getting NaN values for the stock data. 不知道为什么我要获取股票数据的NaN值。
Raw data (df) looks like this: 原始数据(df)如下所示:
MO
65.67
65.74
66.064
65.99
65.8801
65.87
65.89
65.9
65.73
65.67
...
...
If you have a dataframe df containing MO
then you can use set_index ie 如果您的数据框df包含
MO
则可以使用set_index,即
df = df.set_index(pd.timedelta_range('1 days 9 hours 30 minutes', periods=len(df), freq='min'))
Output : 输出:
MO 1 days 09:30:00 65.6700 1 days 09:31:00 65.7400 1 days 09:32:00 66.0640 1 days 09:33:00 65.9900 1 days 09:34:00 65.8801 1 days 09:35:00 65.8700 1 days 09:36:00 65.8900 1 days 09:37:00 65.9000 1 days 09:38:00 65.7300 1 days 09:39:00 65.6700
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.