[英]Is there a Scala “range” method with fractional step size (similar to Python)?
This works: 这有效:
scala> 0 to 24 by 5
res16: scala.collection.immutable.Range = Range(0, 5, 10, 15, 20)
Negative integer works, too: 负整数也适用:
scala> 0 to 24 by -1
res17: scala.collection.immutable.Range = Range()
Demands an integer: 需要一个整数:
scala> 0 to 24 by 0.5
<console>:40: error: type mismatch;
found : Double(0.5)
required: Int
0 to 24 by 0.5
^
Explicitly define a range of Double
s: 明确定义
Double
的范围:
scala> 0.0 to 24.0 by 0.5
// res0: scala.collection.immutable.NumericRange[Double] = NumericRange(0.0, 0.5, 1.0, ...)
A Range
works with Int
only. Range
仅适用于Int
。 NumericRange
is a more generic version of Range
that allows one to define a fractional (ie, of type Double
) step. NumericRange
是Range
一种更通用的版本,它允许您定义分数(即Double
类型)步骤。
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