[英]Custom template pipe fuctions in Tornado
How do you define a custom template pipe function that is available on all template in Tornado. 如何定义一个自定义模板管道功能,该功能可在Tornado中的所有模板上使用。
Trying to achieve something like this: 试图实现这样的目标:
{{ name | transform_me }}
You can pass custom ui_methods
with Application, that will be available in all templates: 您可以将自定义
ui_methods
与Application一起传递,这将在所有模板中可用:
import tornado.ioloop
import tornado.web
class MyHandler(tornado.web.RequestHandler):
def get(self):
self.render("mytemplate.html")
def my_custom_function(handler, *args):
# handler is the RequestHandler of current handled request
# args are the agrs passed through template
return 'my_custom {}'.format(str(args))
if __name__ == "__main__":
application = tornado.web.Application(
[(r"/", MyHandler),],
# expose function to the templates
ui_methods={'my_custom_function': my_custom_function}
)
application.listen(8888)
tornado.ioloop.IOLoop.instance().start()
and template file 和模板文件
{{ my_custom_function('adsadasda', 'qweqweq') }}
You can have your controllers share a Base RequestHandler whose get_template_namespace
method is overwritten. 您可以让您的控制器共享一个基本RequestHandler,其
get_template_namespace
方法将被覆盖。
You probably want to have a filters module. 您可能想要一个过滤器模块。
filters.py filters.py
def transform_me(value):
# transform value
return transformed_value
filters = {
'transform_me': transform_me
}
Shared base class 共享基类
You can add your filters to the template namespace. 您可以将过滤器添加到模板名称空间。 When
render
is called from handlers that inherit from BaseRequestHandler
, your filters will be available. 当
render
是从继承处理程序称为BaseRequestHandler
,您的过滤器将可用。
from filters import filters
class BaseRequestHandler(RequestHandler):
def get_template_namespace(self):
namespace = super(BaseRequestHandler, self).get_template_namespace()
namespace.update(filters)
return namespace
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