在两列中获取具有相同值的行数据

Question

I tried this : this code :

$sql="SELECT DISTINCT t_no,cust_name
FROM menu_order
WHERE b_id IN (
    SELECT b_id,m_name
    FROM menu_order
    GROUP BY b_id
    HAVING COUNT(*) > 1
)";


$result = mysql_query($sql);
$row =  mysql_fetch_array($result);

     echo $row['t_no'];
     echo $row['cust_name'];
while ($row = mysql_fetch_assoc($result, MYSQL_ASSOC)) {

    $name = $row['m_name'];
    $n = explode(',', $name);
    foreach ($n as $d) {
        if ($d !== '') { // because before first comma or after last can be empty
            echo $d.",".PHP_EOL;

        }

    }

}

Please can any one tell how to fetch data with t_no(table number) in common in php. Here, b_id(booking_id) is foreign key .

Expected Output is :

1    |T03  | 2017-08-07 | Dal Fry,Sahi Paneer,Aloo Paratha | 2,1,1

Here is the database:

Answer 1

You can use GROUP BY with GROUP_CONCAT , eg:

SELECT b_id, t_no, date, GROUP_CONCAT(m_name), GROUP_CONCAT(quantity)
FROM table
GROUP BY b_id, t_no, date;

Here's MySQL'd documentation for GROUP_CONCAT() function.

Answer 2

I think there is a problem in your query.. your sub query will return two columns including name, but the b_id IN() would only require b_id. Remove m_name from your sub query.