查找文本中的数字

Question

I have a file with the following content:

&ACCESS RVP1
&REL 3
&PARAM DISKPATH = KRC:\R1\Program\new
DEF SETUP_WELD()
;call LASER_EN();

$out[27]=false;  START=OFF
$out[26]=false;  STROBE=OFF
$out[25]=false;  SELECT 8=OFF
$out[24]=false;  SELECT 7 =OFF
$out[23]=false;  SELECT 6 =OFF
$out[22]=false;  SELECT 5 =OFF
$out[21]=false;  SELECT 4 =OFF
$out[20]=false;  SELECT 3 =OFF
$out[19]=false;  SELECT 2 =OFF
$out[18]=false;  SELECT 1 =OFF
$out[17]=false;  SELECT 0 =OFF
$out[28]=true;  ENABLE=ON

END

I need to find the value,that in the brackets [], and write it into array. In result, I should get next result :

[ '27', '26','25','24','23','22','21','20','19','18','17','28']

I have to do it using Python. I'm pretty new to this, could you , please, , give me a hint what is the most proper way to do it?

My idea was something like this: I read the file into array,and then I was thinking about using the search in element of array:

def reading():
    with open ('Setup_Weld.src') as f:
        array1=[row.strip() for row in f]

But I don't know how to search in elements of array.

UPD: The answer was found. The working code is:

def reading():
    with open ('Setup_Weld.src') as f:
        stripped=[row.strip() for row in f]
        setup_weld_num = [re.search(r'\[(.*?)\]',i).group(1) for i in stripped if re.search(r'\[(.*?)\]',i)]
        print(setup_weld_num)
reading()

Answer 1

Use regex

import re
with open(file_name) as file_object:
    data=file_object.read().replace('\n', '')
    re.findall(r"\[(.*?)\]",data)

Answer 2

try regex this is what you want,

import re
def reading():
    with open ('Setup_Weld.src') as f:
        stripped=[row.strip() for row in f]
        my_num_list = [re.search(br'\[(.*?)\]',i).group(1) for i in stripped if re.search(br'\[(.*?)\]',i)]
        print(my_num_list)
reading()        

python3 output,

mohideen@botvfx-dev:~/Desktop$ python3 run.py 
[b'27', b'26', b'25', b'24', b'23', b'22', b'21', b'20', b'19', b'18', b'17', b'28']
mohideen@botvfx-dev:~/Desktop$ 

here is my output,

Answer 3

Since the format is so simple, you can do this without regex, just using Python's string methods. Here's an adaptation of your start:

def reading():
    with open ('Setup_Weld.src') as f:
        array1=[row.strip() for row in f]
        return [line[5:].split(']')[0] for line in array1]

This removes the first four characters of each line, and then keeps the part before the closing bracket.

Output:

['27', '26', '25', '24', '23', '22', '21', '20', '19', '18', '17', '28']