Javascript中基于某些键值对数组进行排序，然后根据另一个键值对数组进行再次排序

Question

An array contains the list of values as below:

    Object {status: "Pen"
    apptDate:"12-06-2001 04:00 PM "
    func:"OOS"}

  Object {status: "Pen"
    apptDate:"14-03-2001 04:00 PM "
    func:"OOS"}

    Object {status: "Pen"
    apptDate:"15-09-2001 04:00 PM "
    func:"OOS"}

 Object {status: "Pen"
    apptDate:"11-01-2001 04:00 PM "
    }

   Object {status: "Pen"
    apptDate:"10-02-2001 04:00 PM "
    }

Need to create a new array based on the current array that will have the object.func value as "OOS" should be pushed first inside the array while keeping the apptDate in asc order, incase no value present in object.func then sort the sort the array based on apptDate in asc order

Answer 1

With an ISO 8601 date string, you could use String#localeCompare , while respecting 'OOS' sorting on top.

 var array = [{ status: "Pen", apptDate: "2001-06-12 04:00", func: "OOS" }, { status: "Pen", apptDate: "2001-03-14 04:00", func: "OOS" }, { status: "Pen", apptDate: "2001-09-15 04:00", func: "OOS" }, { status: "Pen", apptDate: "2001-01-11 04:00" }, { status: "Pen", apptDate: "2001-02-10 04:00" }]; array.sort(function (a, b) { return (b.func === 'OOS') - (a.func === 'OOS') || a.apptDate.localeCompare(b.apptDate); }); console.log(array); 

 .as-console-wrapper { max-height: 100% !important; top: 0; } 

Answer 2

You can use array.sort with a comparing function such as this:

function(a,b){
    if(a.func && a.func == "OOS" && a.func != b.func){
    return -1;
  } else {
    return new Date(a.apptDate) - new Date(b.apptDate);
  }
}

Note: I've updated some dates to make them valid.

 var arr = [{ status: "Pen", apptDate: "12-18-2001 04:00 PM ", func: "OOS" }, { status: "Pen", apptDate: "9-18-2001 04:00 PM ", func: "OOS" }, { status: "Pen", apptDate: "11-18-2001 04:00 PM ", func: "OOS" }, { status: "Pen", apptDate: "11-18-2001 04:00 PM " }, { status: "Pen", apptDate: "10-18-2001 04:00 PM " }]; arr.sort(function(a,b){ if(a.func && a.func == "OOS" && a.func != b.func){ return -1; } else { return new Date(a.apptDate) - new Date(b.apptDate); } }); console.log(arr);