如何用gcc编译C程序？

Question

I wrote a simple program named bc to call dir in Windows 10 cmd via C.

This is what the script looks like:

#include <stdlib.h>

int main()
{
    system("dir");
    return 0;
}

I typed this in cmd

gcc b.c
b

but it returns

J:\fundamental of C programming>b
'b' is not recognized as an internal or external command, operable program or batch file.

This is how I add path

I don't think it is path matter.

So how can I fix it?

Answer 1

You need to run

gcc b.c -o b.exe

Without -o option it'll use the default output executable name which is a.exe on Windows and a.out on *nix systems . You can easily see the a.exe with the dir command

-o file

• Place output in file file. This applies to whatever sort of output is being produced, whether it be an executable file, an object file, an assembler file or preprocessed C code.

• If -o is not specified, the default is to put an executable file in a.out , the object file for source.suffix in source.o , its assembler file in source.s , a precompiled header file in source.suffix.gch , and all preprocessed C source on standard output.

https://gcc.gnu.org/onlinedocs/gcc/Overall-Options.html

For more information read Determining C executable name

Of course you can also run a instead of b

Answer 2

Compile like this

gcc -o b b.c

by specifying output filename

-o <output_file>

Answer 3

尝试在Windows中更新bin路径变量，打开下一个链接以查看操作方法： http : //www.c4learn.com/c-programming/run-c-program-command-prompt-windows/