Symfony3-注销路径生成方法

Question

在Symfony应用程序中使用path('logout')和logout_path()有什么区别？

Answer 1

When you use path('logout') you call RoutingExtension::getPath . Route with name 'logout' can point to whatever URL you define – eg to '/lorem-ipsum' and call whatever controller's action – eg DefaultController::loremIpsumAction .

When you use logout_path() you call LogoutUrlExtension::getLogoutPath , which generate logout URL for current firewall using LogoutUrlGenerator .

Answer 2

path :

{{ path(name, parameters = [], relative = false) }}

path returns the relative URL (without the scheme and host) for the given route. If relative is enabled, it'll create a path relative to the current path. More information in Linking to Pages , in your case /logout is your route and i suggest you read about Routing more to understand its components and purpose .

Read Routing to learn more about the Routing component Routing . Since Symfony 2.7 you can use logout_path

{{ logout_path(key = null) }}

key is optional and its type is string logout_path Generates a relative logout URL for the given firewall. If no key is provided, the URL is generated for the current firewall the user is logged into.