[英]ASP.NET MVC 5 JsonResult & Ajax - MVC JQuery error
Thanks to @NikhilGhuse, which solution have been sent to me (please mark his answer). 感谢@NikhilGhuse,该解决方案已发送给我(请标出他的回答)。 I can apply this solution to my data these are the results and the keys:
我可以将此解决方案应用于我的数据,这些是结果和关键:
First of all my model need to send a List to the controller. 首先,我的模型需要发送一个List到控制器。 This is my my function to send the List:
这是我发送列表的功能:
public List<VistaModelo> SegundaConsulta()
{
//Web.Config
Entities db = new Entities();
var consulta = from varLocal in db.LecturaContadorLuzAANDRES
group varLocal by varLocal.dispositivo into subconsulta
select subconsulta.OrderByDescending(t => t.unixtime).FirstOrDefault();
List<LecturaContadorLuzAANDRES> lista = consulta.ToList();
List<VistaModelo> listaVistaModelo = new List<VistaModelo>();
foreach (LecturaContadorLuzAANDRES b in lista)
{
VistaModelo objLista = b.pasaObjetoAVistaModelo();
listaVistaModelo.Add(objLista);
}
return listaVistaModelo;
}
Then in my controller I need two functions: 然后在我的控制器中,我需要两个功能:
Consulta 6. Read the list and transform to JSON (you need: using Newtonsoft.Json; in the controller: Consulta 6.阅读列表并转换为JSON(您需要:在控制器中使用Newtonsoft.Json ;:
public JsonResult Consulta6()
{
var Consulta = new ConsultaContraBD();
List<VistaModelo> miSegundaConsulta = Consulta.SegundaConsulta();
return Json(miSegundaConsulta, JsonRequestBehavior.AllowGet); //El JsonRequest Behaviour permite que se devuelva información de JSON en un getRequest.
}
Consulta7. Consulta7。 From this method I make the View:
通过这种方法,我可以创建视图:
public ActionResult Consulta7()
{
return View();
}
Finally I need Ajax into the script to read the information pass to method Consulta6. 最后,我需要在脚本中使用Ajax来读取传递给Consulta6方法的信息。 Note: Remember to load the packages json2.js and jquery-3.0.0.js
注意:请记住加载包json2.js和jquery-3.0.0.js
@{
ViewBag.Title = "Consulta7";
}
<script src="~/Script/jquery-3.0.0.js"></script>
<script src="~/Script/json2.js"></script>
<script type="text/javascript">
$(function () {
$('#btonLista').on("click", function (e) {
e.preventDefault();
$.ajax
({
url: '/Home/Consulta6/',
type: 'get',
dataType: 'json',
success: function (data) {
$(data).each(function (index, item) {
$('#ulLista').append("<li>" + item.consumo + "</li>")
});
}
});
});
});
</script>
<div>
<input type="button" id="btonLista" value="Click" name="" />
<ul id="ulLista"></ul>
</div>
The final result is a page where you click a button and returns the list. 最终结果是一个页面,您单击一个按钮并返回列表。
<script type="text/javascript">
$(function ()
{enter code here
$('#btonLista').on("click", function (e)
{
e.preventDefault();
$.ajax
({
url: '/Home/Consulta52/',
type: 'GET',
dataType: 'json',
success: function (data) {
$(data).each(function (index, item) {
$('#ulLista').append("<li>"+item.consumo+"</li>")
});
}
});
});
});
</script>
My two controllers: 我的两个控制器:
public ActionResult Consulta51()
{
return View();
}
public JsonResult Consulta52()
{
var Consulta = new ConsultaContraBD();
var miSegundaConsulta = Consulta.SegundaConsulta();
return Json(miSegundaConsulta.ToList(), JsonRequestBehavior.AllowGet);
}
/// My Sample Starts here ///我的示例从这里开始
//Controller //控制器
namespace Sample.Controllers
{
public class HomeController : Controller
{
//
// GET: /Home/
public ActionResult Index()
{
return View();
}
public JsonResult Consulta52()
{
modelCS model = new modelCS();
List<Department> ds = model.getList();
return Json(ds, JsonRequestBehavior.AllowGet);
}
}
}
//Index.cshtml //Index.cshtml
@{
ViewBag.Title = "Index";
}
<h2>
Index</h2>
<script src="../../scripts/jquery-2.1.4.js" type="text/javascript">
</script>
<script src="../../scripts/json2.js" type="text/javascript"></script>
<script type="text/javascript">
$(function () {
$('#btonLista').on("click", function (e) {
e.preventDefault();
$.ajax
({
url: '/Home/Consulta52/',
type: 'get',
dataType: 'json',
success: function (data) {
$(data).each(function (index, item) {
$('#ulLista').append("<li>" + item.DepartmentName + "</li>")
});
}
});
});
});
</script>
<div>
<input type="button" id="btonLista" value="Click" name="" />
<ul id="ulLista">
</ul>
</div>
And My Model Class goes like this 我的模型课是这样的
public class modelCS
{
string constr = "Data Source=.;Initial Catalog=test1;Integrated Security=True";
List<Department> newDept = new List<Department>();
public List<Department> getList()
{
SqlConnection con = new SqlConnection(constr);
// SqlCommand cmd = new SqlCommand("select * from Department", con);
con.Open();
SqlDataAdapter da = new SqlDataAdapter("select * from Department", con);
DataSet ds = new DataSet();
da.Fill(ds);
var td = ds.Tables[0];
// List<Department> newDept = new List<Department>();
foreach (DataRow t in td.Rows)
{
newDept.Add(new Department() { DepartmentId = (int)t.ItemArray[0], DepartmentName = t.ItemArray[1].ToString() });
}
return newDept;
//List<string> list = listT
}
}
Department class 部门课
public class Department
{
public int DepartmentId { get; set; }
public string DepartmentName { get; set; }
}
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