PHP array_filter

Question

$alllist = array(
    "link" => $link, 
    "title" => $title, 
    "imgurl" => $imgURL,
    "price" => $price,
    "mname" => $merchantname,
    "description" => $description,
);

$all[] = $alllist;

I am trying to filter the array $all where mname is a certain value, let's say 'Amazon'. How do I do that?

I tried this, but it did not work:

reset($all);

$all_filter = array_filter($all, function(filter) use ($all) {
    $key = key($all);
    next($all);
    return key($all) === 'Amazon';
});

Answer 1

I think this what you want:

$name = 'Amazon'; 

$all_filter = array_filter($all, function (array $item) use ($name) {
    return array_key_exists('mname', $item) && $item['mname'] === $name;
});

Answer 2

$all[] = array("link"=> 1, "title"=> 2, "imgurl"=> 3, 
"price"=>4, "mname"=>'Amazon', "description"=>5);


$all[] = array("link"=> 1, "title"=> 2, "imgurl"=> 3, 
"price"=>4, "mname"=>'Facebook', "description"=>5);

$filtered = array_filter($all, function($item) {
return $item['mname'] === 'Amazon';
});

var_dump($filtered);

Answer 3

array_filter() will iterate over the array for you. You don't need to call reset() or next() .

You should look at the array_filter() documentation for more info and examples.

$all_filter = array_filter($all, function($item) {
    return $item['mname'] === 'Amazon';
});

Answer 4

It looks like you're making it more complex than it needs to be. The callback should just return a boolean value. If you don't want to hard-code the value you want to filter by (eg 'Amazon' ), you can pass it into the callback with use .

$filter_value = 'Amazon';

$all_filter = array_filter($all, function($item) use($filter_value) {
    // without use($filter_value), $filter_value will be undefined in this scope
    return $item['mname'] == $filter_value;
});

Returning the boolean expression $item['mname'] == $filter_value; will determine which items have mname values that match the filter value, and those items will be included in the result.