Python beautifulsoup按行号打印

Question

Okay so I'm currently using python beautifulsoup to output a specific line from a html file, since the html contains multiple of the same div class, it'll output every div containing the same class, example of this

CONTENT:

<div class=border>aaaa</a>
<div class=border>example</a>
<div class=border>runrunrun</a>

OUTPUT:

<div class=border>aaaa</a>
<div class=border>example</a>
<div class=border>runrunrun</a>

Now I only want #2 of div class border,

<div class=border>example</a>

now if i view source within chrome, it'll show content in number lines, so line 1 will contain

<div class=border>aaaa</a> 

& line 2 will contain

<div class=border>example</a>

is it possible to output via numbered line using beautiful soup?

Answer 1

find_all returns a list, so you can index it with [1] to get the second element.

from bs4 import BeautifulSoup

html_doc = """<div class=border>aaaa</a>
<div class=border>example</a>
<div class=border>runrunrun</a>"""

soup = BeautifulSoup(html_doc, 'html.parser')

soup.find_all(class_="border")[1]

returns

<div class="border">example</div>

Answer 2

If you have the list with say 200 elements generated by soup.find_all... If the list is called div_list, you could just do an index loop (you want index 1,4,7 etc...)

count = 1
while True:
    try:
        print(div_list[count])
        count+=3
    except:
    # happens because of index error
        break

Or even shorter:

count = 1
while count<= len(div_list):
    print(div_list[count])
    count+=3