如何从多个文件中打印相应的行？

Question

I have a program which prints 3 bits of information, forename, surname and date of birth. These are all stored in separate text files. Each line of one text file goes with the same line number of the other text files. I want to print the information like this:

John Smith 02/01/1980

My code does this but is very long, is there a way to shorten my code and still print the information the way i want. The code below prints the information of 10 people.

def reportone():
    print()
    for file in ["Forename", "Surname", "Date of birth"]:
        with open(file) as f:
            print(f.readlines()[1-1], end='')
    print()
    for file in ["Forename", "Surname", "Date of birth"]:
        with open(file) as f:
            print(f.readlines()[2-1], end='')
    print()
    for file in ["Forename", "Surname", "Date of birth"]:
        with open(file) as f:
            print(f.readlines()[3-1], end='')
    print()
    for file in ["Forename", "Surname", "Date of birth"]:
        with open(file) as f:
            print(f.readlines()[4-1], end='')
    print()
    for file in ["Forename", "Surname", "Date of birth"]:
        with open(file) as f:
            print(f.readlines()[5-1], end='')
    print()
    for file in ["Forename", "Surname", "Date of birth"]:
        with open(file) as f:
            print(f.readlines()[6-1], end='')
    print()
    for file in ["Forename", "Surname", "Date of birth"]:
        with open(file) as f:
            print(f.readlines()[7-1], end='')
    print()
    for file in ["Forename", "Surname", "Date of birth"]:
        with open(file) as f:
            print(f.readlines()[8-1], end='')
    print()
    for file in ["Forename", "Surname", "Date of birth"]:
        with open(file) as f:
            print(f.readlines()[9-1], end='')
    print()
    for file in ["Forename", "Surname", "Date of birth"]:
        with open(file) as f:
            print(f.readlines()[10-1], end='')
reportone()

Answer 1

File objects are iterators , so you could use zip() to aggregate the corresponding lines from all the files, eg

with open("file1.txt") as f1, open("file2.txt") as f2, open("file3.txt") as f3:
    for lines in zip(f1, f2, f3):
        print(*map(str.strip, lines))

Answer 2

You can try this:

titles = ["Forename", "Surname", "Date of birth"]

data = [open("{}.txt".format(i)).readlines() for i in titles]

for forename, surname, dob in zip(*data):
     print(forename, surname, dob)