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检查元素是否存在python selenium

[英]Check if element exists python selenium

I'm trying to locate element by 我正在尝试找到元素

element=driver.find_element_by_partial_link_text("text")

in Python selenium and the element does not always exist. 在Python selenium中,元素并不总是存在。 Is there a quick line to check if it exists and get NULL or FALSE in place of the error message when it doesn't exist? 是否存在快速行以检查它是否存在并在错误消息不存在时获取NULL或FALSE代替错误消息?

You can implement try / except block as below to check whether element present or not: 你可以实现如下的try / except块来检查元素是否存在:

from selenium.common.exceptions import NoSuchElementException

try:
    element=driver.find_element_by_partial_link_text("text")
except NoSuchElementException:
    print("No element found")

or check the same with one of find_elements_...() methods. 或使用find_elements_...()方法之一检查相同内容。 It should return you empty list or list of elements matched by passed selector, but no exception in case no elements found: 它应该返回由传递的选择器匹配的空列表或元素列表,但是如果没有找到元素则没有异常:

elements=driver.find_elements_by_partial_link_text("text")
if not elements:
    print("No element found")  
else:
    element = elements[0]  

Sometimes the element does not appear at once, for this case we need to use explicit wait: 有时元素不会立即出现,对于这种情况,我们需要使用显式等待:

browser = webdriver.Chrome()
wait = WebDriverWait(browser, 5)

def is_element_exist(text):
    try:
        wait.until(EC.presence_of_element_located((By.PARTIAL_LINK_TEXT, text)))
    except TimeoutException:
        return False

Solution without try/ except : 解决方案没有try/ except

def is_element_exist(text):
    elements = wait.until(EC.presence_of_all_elements_located((By.PARTIAL_LINK_TEXT, text)))
    return None if elements else False

How explicit wait works you can read here . 你可以在这里阅读明确的等待。

Imports: 进口:

from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

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