编写C程序以将数组中的数字排列为一系列奇数和偶数

Question

I've made an attempt to create the above program,but there's some error.Here's my program

#include <stdio.h>
#include <conio.h>

void main()
{
    int a[20],o[20],e[20],c[40],i,j,k,l,n;
    printf("enter size of array");
    scanf("%d",&n);
    printf("enter array");
    for(i=1;i<=n;i++)
    {
        scanf("%d",&a[i]);
    }
    for(i=1;i<=n;i++)
    {
        for(j=1;j<=n;j++)
        {
            for(k=1;k<=(n-j);k++)
            {
                if(a[i]%2==0)
                {
                    o[j]=a[i];
                    break;
                }
        else
        {
            e[k]=a[i];
        }
        }
        }
    }
    for(i=1;i<=j;i++)
    {
        c[l]=o[i];
    }
    for(i=1;i<=k;i++)
    {
        c[l+k]=e[k];
    }
    printf("The new array is");
    for(l=1;l<=(j+k);l++)
    {
        printf(" %d ",c[l]);
    }
    getch();
}

Can anybody please help me rectify the error in the above program?Can someone also give me a few tips on how to become a good C programmer?

Answer 1

The problem is probably because you never initialize the variable l . Using an uninitialized variables yields in undefined behaviour (google that).

Also your array indexes start at 1 as for example here:

for (i = 1; i <= n; i++)

In C array indexes start at 0, so you should write this:

for (i = 0; i < n; i++)

This appies to all your other for loops.

• There may be other problems though.
• Your program looks overly complicated
• Using variable names such as odd instead of o and even instead of e would make your program much easier to read.
• Your program is poorly formatted. Correct formatting is essential to readbility