Ajax数据插入数据库不起作用

Question

I am trying to build a comment system for my website using Ajax, jQuery and PHP. My site has the lot of queries, how can I submit comments every query separate?

Ajax code

 $(document).ready(function()
   {
   $("#comq").click(function() {
       var comment=$("#comment").val();
               var qid=$("#qid").val();
       $.ajax({
        cache:false,
        type:"post",         
         url:"jquery.php",
data:{comments:comment, qid:qid},
        success:function(data)
        {
    $(".cmt").html(data);
        }
     });
   });
  });

when I submit the comments, comments only inserted but query (qid) not inserted in DB (database table)

php code

 if(isset($_POST["comments"])){         
    $comment=$_POST['comments'];
    $qid= $_POST['qid'];
    $reslt_user= mysqli_query($connection,"SELECT * FROM tbl_users,`queries` where id='".$_SESSION['id']."' AND  qid= '".$qid."'");
    $row_lat_lng= mysqli_fetch_array($reslt_user);
       $stmt = mysqli_query($connection,"INSERT INTO comments set uid='".$_SESSION['id']."',comments='".$comment."',reply='".$reply."', qid= '".$qid."' ");

Html code

     <div id="comments" class="cmt" >
    <input class="commentbox"id="comment"name="comments"placeholder="Comment 
               Here" maxlength="50">
    <input type="hidden"id="qid "name="qid">
     <button type="button" id="comq" name="compost" class="butn2" value="submit">
    </button>
                        </div>

How to post comments as per queries (how to insert)?

Answer 1

See this line here,

<input type="hidden" id="qid "name="qid">
                        ^^^^

• Misplaced closing " for id attribute.
• value attribute is missing from the hidden input element.

So the hidden input element should be like this:

<input type="hidden" id="qid" name="qid" value="SOME VALUE" />

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Sidenote: Learn about prepared statement because right now your queries are susceptible to SQL injection attack. Also see how you can prevent SQL injection in PHP .