如何在Python中获取* xlsx文件路径名的字符串？

Question

there are several different format files in the Documents

I need to get a string which is the *xlsx format files path I using below code ，but it return a error as like below

PATH= u'F:\Workfiles\周报\\forupdate'
filepath = os.path.join(PATH,str(os.listdir(PATH)))

IOError: [Errno 2] No such file or directory: u"F:\\Workfiles\\\周\报\\forupdate\\[u'suxl20170821.xlsx']"

does any body knows how to get the files path ？？？

Answer 1

you can use listdir to find the paths

import os
for file in os.listdir("F:\Workfiles\周报\forupdate"):
    if file.endswith(".xlsx"):
        print(os.path.join("F:\Workfiles\周报\forupdate", file))

or You can use glob

import glob, os
os.chdir("F:\Workfiles\周报\forupdate")
for file in glob.glob("*.xlsx"):
    print(file)