MySQL结果转换为数据透视表与PHP

Question

   products(prod_id, prod_name,...)
   attribute_key(attr_key_id, attr_name)
   attributes_values(attr_val_id, attr_key_id, value)
   product_attr_values(id,product_id,attr_val_id)

I have defined MYSQL result as an array definition. The problem is i have to concatenate same attribute with different values for the same product with comma(;). But i can get result without concatenating it. Help appreciated.

$shop = Array
(
"0" => Array
    (
        "id" => 9,
        "prodname" => 'Ramkinkar Baij',
        "attribute_name" => 'Author',
        "value" => 'sabsyasachi das'
    ),

"1" => Array
    (
        "id" => 10,
        "prodname" => 'Ramkinkar Baij',
        "attribute_name" => 'Author',
        "value" => 'Ela Datta'
    ),

"2" => Array
    (
        "id" => 11,
        "prodname" => 'Ramkinkar Baij',
        "attribute_name" => 'Editor',
        "value" => 'Sathi Basu'
    ),

"3" => Array
    (
        "id" => 12,
        "prodname" => 'Ramkinkar Baij',
        "attribute_name" => 'Editor',
        "value" => 'Radha Prasad Gupta'
    ),

"4" => Array
    (
        "id" => 13,
        "prodname" => 'Ramkinkar Baij',
        "attribute_name" => 'Place_of_Publication',
        "value" => 'Panagarh, Burdwan, West Bengal'
    ),

"5" => Array
    (
        "id" => 14,
        "prodname" => 'Rendava Prapancha Telugu Mahasabhalu, 1981',
        "attribute_name" => 'Author',
        "value" => 'sabsyasachi das'
    ),

"6" => Array
    (
        "id" => 15,
        "prodname" => 'Rendava Prapancha Telugu Mahasabhalu, 1981',
        "attribute_name" => 'Author',
        "value" => 'Ela Datta'
    ),

"7" => Array
    (
        "id" => 16,
        "prodname" => 'Rendava Prapancha Telugu Mahasabhalu, 1981',
        "attribute_name" => 'Translated_by',
        "value" => 'partha dasgupta'
    ),

"8" => Array
    (
        "id" => 17,
        "prodname" => 'Rendava Prapancha Telugu Mahasabhalu, 1981',
        "attribute_name" => 'Editor',
        "value" => 'Bandana Mukhopadhay'
    ),

"9" => Array
    (
        "id" => 18,
        "prodname" => 'Rendava Prapancha Telugu Mahasabhalu, 1981',
        "attribute_name" => 'Editor',
        "value" => 'Sathi Basu'
    ),

"10" => Array
    (
        "id" => 19,
        "prodname" => 'Rendava Prapancha Telugu Mahasabhalu, 1981',
        "attribute_name" => 'Translated_Title',
        "value" => '(Second World Telugu Conference, 1981)'
    ),

"11" => Array
    (
        "id" => 20,
        "prodname" => 'Rendava Prapancha Telugu Mahasabhalu, 1981',
        "attribute_name" => 'Place_of_Publication',
        "value" => 'Hyderabad'
    ),

"12" => Array
    (
        "id" => 21,
        "prodname" => 'Rendava Prapancha Telugu Mahasabhalu, 1981',
        "attribute_name" => 'Foreword',
        "value" => 'Information on Government organisations of Art and Culture in Andhra Pradesh'
    ),

"13" => Array
    (
        "id" => 22,
        "prodname" => 'Rendava Prapancha Telugu Mahasabhalu, 1981',
        "attribute_name" => 'Descriptive_Tags',
        "value" => 'Conference, Language'
    )

);


$groups = array();

foreach($shop as $key => $array){
//$type is not necessary, it's just for clarity below
$product = $array['prodname'];



if( !isset($groups[$product]) ){
    $groups[$product] = array();
    $groups[$product]['prod'] = $array['prodname'];
}


$groups[$product][$array["attribute_name"]] = $array['value'];

}
//then combine the groups into a master array
$out = array();
foreach($groups as $g){
$out[] = $g;
}
echo '<pre>'. print_r($out, true).'</pre>';
print "<pre>";
//print_r($groups);
print "</pre>";

Answer 1

使用MySQL的GROUP BY和GROUP_CONCAT函数。

SELECT prod_name, GROUP_CONCAT(CONCAT(attr_name, ': ', value) SEPARATOR ', ') AS attributes FROM [your tables and joins] GROUP BY prod_id