无法在文件资源管理器中打开子目录？ -Node.js

Question

I can't figure out why I can't open a subdirectory of "My Documents" in Node.js.

My current code:

function fileExplorer() {
    var spawn = require('child_process').spawn,
    child    = spawn('C:\\Windows\\explorer.exe', 
    ["%userprofile%\\documents"]);
  }

Works completely fine to fire up the user's "My Documents" folder. However, if I want to open up a directory inside of "My Documents" like say "My Documents/Extra Stuff" the following doesn't work:

function fileExplorer() {
    var spawn = require('child_process').spawn,
    child    = spawn('C:\\Windows\\explorer.exe', 
    ["%userprofile%\\documents\\extra stuff"]);
  }

What am I missing? Forgive me if something is wrong with what I'm asking, I have a design oriented brain and am more familiar with HTML, CSS and some Javascript.

Answer 1

您可以在process.env.USERPROFILE下的代码中访问%USERPROFILE%环境变量，因此可以使用path.join(process.env.USERPROFILE, 'Documents/extra stuff')使它起作用path.join(process.env.USERPROFILE, 'Documents/extra stuff')