awk在一个文件中两个单词之间的所有行出现多次

Question

I am trying to get all lines in some SQL code between WHERE and GROUP, I have the below, which gets me the first occurrence of text between WHERE and GROUP, but there are multiple occurrences of the same I am after

awk '/WHERE/{p=1} p; /GROUP/{exit}' filename.txt

Output

WHERE something Some SQL code GROUP BY something

There are multiple sections of the code that start with WHERE and end with GROUP BY with in the file I would like to output

Can anybody help?

Answer 1

It is better in awk to do something along these lines:

awk '/WHERE/{f=1} f; /GROUP/{f=0}' file

The awk range operator , works similarly to sed . However, it is difficult to modify and you limit what awk can do.

Once your awk habit includes using a flag (rather than a range) it will be easier to print between marks such as:

$ echo "a
b
c
---
d
e
f
---
g
h" | awk '/^---$/{f= ! f; next}  f'
d
e
f

Which is impossible with the range operator.

Answer 2

awk '/WHERE/,/GROUP/' filename.txt