[英]Subtract two columns of different tables with different number of rows
How can I write a single query that will give me SUM(Entrance.quantity) - SUM(Buying.quantity) group by product_id. 如何编写一个查询,该查询将按product_id为我提供SUM(Entrance.quantity)-SUM(Buying.quantity)组。
The problem is in rows that not exist in the first or second table. 问题出在第一张或第二张表中不存在的行中。 Is possible to do this?
可以这样做吗?
Entrance: 入口:
+---+--------------+---------+
| id | product_id | quantity|
+---+--------------+---------+
| 1 | 234 | 15 |
| 2 | 234 | 35 |
| 3 | 237 | 12 |
| 4 | 237 | 18 |
| 5 | 101 | 10 |
| 6 | 150 | 12 |
+---+--------------+---------+
Buying: 购买:
+---+------------+-------------+
| id | product_id | quantity|
+---+------------+-------------+
| 1 | 234 | 10 |
| 2 | 234 | 20 |
| 3 | 237 | 10 |
| 4 | 237 | 10 |
| 5 | 120 | 15 |
+---+------------+------------+
Desired result: 所需结果:
+--------------+-----------------------+
| product_id | quantity_balance |
+--------------+-----------------------+
| 234 | 20 |
| 237 | 10 |
| 101 | 10 |
| 150 | 12 |
| 120 | -15 |
+--------------+-----------------------+
This is tricky, because products could be in one table but not the other. 这很棘手,因为产品可以放在一个表中,而不能放在另一个表中。 One method uses
union all
and group by
: 一种方法是使用
union all
和group by
:
select product_id, sum(quantity)
from ((select e.product_id, quantity
from entrance e
) union all
(select b.product_id, - b.quantity
from buying b
)
) eb
group by product_id;
SELECT product_id ,
( Tmp1.enterquantity - Tmp2.buyquantity ) AS Quantity_balance
FROM entrance e1
CROSS APPLY ( SELECT SUM(quantity) AS enterquantity
FROM Entrance e2
WHERE e1.product_id = e2.product_id
) Tmp1
CROSS APPLY ( SELECT SUM(quantity) AS buyquantity
FROM Buying b2
WHERE e1.product_id = b2.product_id
) Tmp2
GROUP BY Product_id,( Tmp1.enterquantity - Tmp2.buyquantity )
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