MySQL 5.7无法与组一起正常使用

Question

I have upgraded my datababase to mysql 5.7.15, and I keep getting this error message everytime I try to run the following query

SELECT `hired_proj_id` 
FROM `hired_projects` 
WHERE `status_code` = '3' 
  AND `client_id` = 55 
GROUP BY `proj_id` 
ORDER BY `hired_proj_id` DESC;

Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'sandbox.hired_projects.hired_proj_id' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by

I have been look through stackover flow, but was unable to find an answer. Any help would be really appreciated. Thanks!!

Answer 1

I learned yesterday this thanks to Gordon Linoff

All columns in the select should either be columns in the group by or use aggregate functions (sum(), avg(), and so on).

Your query:

  SELECT `hired_proj_id` 
    FROM `hired_projects` 
   WHERE `status_code` = '3' 
     AND `client_id` = 55 
GROUP BY `proj_id` 
ORDER BY `hired_proj_id` DESC

When we check your query we see that the selected 'hired_proj_id' is not in your GROUP BY .

Your query should be like this:

    SELECT `hired_proj_id` 
      FROM `hired_projects` 
     WHERE `status_code` = '3' 
       AND `client_id` = 55 
  GROUP BY `hired_proj_id`,`proj_id` 
  ORDER BY `hired_proj_id` DESC

This is probably your solution.

Answer 2

Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column

the error is clear, either you add the field on the SELECT to the GROUP BY

   SELECT <fieldName>
   FROM yourTable
   WHERE <conditions>
   GROUP BY <fieldName>

OR add an aggregated function on the SELECT

   SELECT SUM(<fieldName>)
   FROM yourTable
   WHERE <conditions>
   GROUP BY <otherfieldName>

Answer 3

Note: MySQL is insecure and is deprecated, use PDO or MySQLi instead.

Here is an implementation with MySQLi,

 <?php

     //MySQLi information

        $db_host     = "localhost";
        $db_username = "username";
        $db_password = "password";

        //connect to mysqli database (Host/Username/Password)
        $connection = mysqli_connect($db_host, $db_username, $db_password) or die("Error " . mysqli_error());

        //select MySQLi dabatase table
        $db = mysqli_select_db($connection, "table") or die("Error " . mysqli_error());

  $sql = mysqli_query($connection, "

    SELECT `hired_proj_id` 
      FROM `hired_projects` 
     WHERE `status_code` = '3' 
       AND `client_id` = 55 
  GROUP BY `hired_proj_id`,`proj_id` 
  ORDER BY `hired_proj_id` DESC

");

    ?>

Answer 4

I am guessing that the query you really want is:

SELECT DISTINCT hired_proj_id 
FROM hired_projects
WHERE status_code = 3 AND client_id = 55 
ORDER BY hired_proj_id DESC;

Notes:

• Don't enclose numeric constants in single quotes -- unless they are really strings.
• No need to use backticks everywhere.