[英]How to display/request JSON Object using Android Volley?
I'm having a problem in Android Studio on how to request JSON Object. 我在Android Studio中遇到有关如何请求JSON对象的问题。
My Logcat can only print String onResponse but not JSONObject value. 我的Logcat只能在String onResponse上打印String,而不能在JSONObject值上打印。 I'm having a problem in line try{} inside AccessActivity.java 我在AccessActivity.java中的try {}行中遇到问题
My code explanation as below. 我的代码说明如下。
I have these JSON Object output that I fetch from mysql database. 我有从mysql数据库中获取的这些JSON对象输出。
{
"access":"PA001",
"password":"123",
"fullname":"ARCADE",
"branch":"HQ",
"section":"MPR"
}
In my PHP code, this is how I fetch the data and encode it as JSON Object. 在我的PHP代码中,这就是我获取数据并将其编码为JSON对象的方式。
access.php access.php
<?php
$conn = mysqli_connect("","","","");
if(
isset($_POST['access']) &&
isset($_POST['password'])
){
$access = $_POST['access'];
$password = $_POST['password'];
$sql = "SELECT * FROM table WHERE access = '$access' AND password = '$password' ";
$result = mysqli_query($conn, $sql);
if($result && mysqli_num_rows($result) > 0){
while($row = mysqli_fetch_array($result)){
$accessdb = $row['access'];
$passworddb = $row['password'];
$fullnamedb = $row['fullname'];
$branchdb = $row['branch'];
$sectiondb = $row['section'];
echo "success_access";
$response = array('access' => $accessdb, 'password' => $passworddb, 'fullname' => $fullnamedb, 'branch' => $branchdb, 'section' => $sectiondb);
echo json_encode($response);
}
mysqli_free_result($result);
} else {
echo "access_failed";
}
}
?>
But my problem occurs in Android Studio, 但是我的问题出现在Android Studio中,
Here's my code . 这是我的代码。
AccessActivity.java AccessActivity.java
public class AccessActivity extends AppCompatActivity{
final String TAG = this.getClass().getName();
EditText etAccess, etPassword;
Button bLogin;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_login);
Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
setSupportActionBar(toolbar);
etAccess = (EditText)findViewById(R.id.etAccess);
etPassword = (EditText)findViewById(R.id.etPassword);
bLogin = (Button)findViewById(R.id.bLogin);
bLogin.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
String url = "http://localhost/access.php";
StringRequest stringRequest = new StringRequest(Request.Method.POST, url, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
Log.e(TAG, "Response is = " + response);
if(response.equals("success_access")){
try {
JSONObject jsonObject = new JSONObject(response);
Log.e(TAG, "JSON Object is = " + jsonObject);
final String accessdb = jsonObject.getString("access");
final String passworddb = jsonObject.getString("password");
final String fullnamedb = jsonObject.getString("fullname");
final String branchdb = jsonObject.getString("branch");
final String sectiondb = jsonObject.getString("branch");
Intent intent = new Intent(AccessActivity.this, NextActivity.class);
intent.putExtra("access", accessdb);
intent.putExtra("password", passworddb);
intent.putExtra("fullname", fullnamedb);
intent.putExtra("branch", branchdb);
intent.putExtra("section", sectiondb);
AccessActivity.this.startActivity(intent);
} catch (JSONException e) {
e.printStackTrace();
}
} else{
Toast.makeText(getApplicationContext(), "Access Error", Toast.LENGTH_SHORT).show();
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(getApplicationContext(), "Volley Error", Toast.LENGTH_SHORT).show();
}
}){
@Override
protected Map<String, String> getParams() throws AuthFailureError {
Map<String, String> params = new HashMap<>();
params.put("access", etAccess.getText().toString());
params.put("password", etPassword.getText().toString());
return params;
}
};
MySingleton.getInstance(getApplicationContext()).addToRequestQueue(stringRequest);
}
});
}
}
UPDATE : 更新:
my logcat display this 我的logcat显示此
08-22 10:22:22.059 19801-19908/com.apps.test D/NetworkSecurityConfig: No Network Security Config specified, using platform default
08-22 10:22:22.064 19801-19801/com.apps.test E/my.com.apps.test.Activity: Response is = success_access{"access":"PA001","password":"123","fullname":"ARCADE","branch":"HQ","section":"HQ"}
08-22 10:22:22.112 19801-19825/com.apps.test D/EGL_emulation: eglMakeCurrent: 0xb3305060: ver 2 0 (tinfo 0xb3303200)
08-22 10:22:22.128 19801-19825/com.apps.test D/EGL_emulation: eglMakeCurrent: 0xb3305060: ver 2 0 (tinfo 0xb3303200)
08-22 10:22:22.134 19801-19825/com.apps.test D/EGL_emulation: eglMakeCurrent: 0xb3305060: ver 2 0 (tinfo 0xb3303200)
08-22 10:22:22.140 19801-19825/com.apps.test D/EGL_emulation: eglMakeCurrent: 0xb3305060: ver 2 0 (tinfo 0xb3303200)
08-22 10:22:23.697 19801-19825/com.apps.test D/EGL_emulation: eglMakeCurrent: 0xb3305060: ver 2 0 (tinfo 0xb3303200)
08-22 10:22:25.751 19801-19825/com.apps.test D/EGL_emulation: eglMakeCurrent: 0xb3305060: ver 2 0 (tinfo 0xb3303200)
08-22 10:22:25.780 19801-19825/com.apps.test D/EGL_emulation: eglMakeCurrent: 0xb3305060: ver 2 0 (tinfo 0xb3303200)
Appreciate if someone can help me to solve this problem. 感谢有人可以帮助我解决此问题。 Thanks. 谢谢。
Try this. 尝试这个。
In the AccessActivity 在AccessActivity中
Intent intent = new Intent(AccessActivity.this, NextActivity.class);
intent.putExtra("access", accessdb);
intent.putExtra("password", passworddb);
intent.putExtra("fullname", fullnamedb);
intent.putExtra("branch", branchdb);
intent.putExtra("section", sectiondb);
AccessActivity.this.startActivity(intent);
change 更改
LoginActivity.this.startActivity(intent);
to 至
AccessActivity.this.startActivity(intent);
In the NextActivity 在NextActivity中
Intent intent = getIntent();
String access = intent.getStringExtra("access");
String password = intent.getStringExtra("password");
String fullname = intent.getStringExtra("fullname");
String branch = intent.getStringExtra("branch");
String section = intent.getStringExtra("section");
Edited 已编辑
change 更改
if(response.equals("success_access")){
}
to 至
if(response.contains("success_access")){
}
And according to your code. 并根据您的代码。 You need to make sure that your current Activity is com.apps.test.AccessActivity
or com.apps.test.AccessActivity
. 您需要确保当前的Activity是com.apps.test.AccessActivity
或com.apps.test.AccessActivity
。
Edited 已编辑
change to 改成
if (response.contains("success_access")) {
String res = response.substring(response.indexOf("{"));
try {
JSONObject jsonObject = new JSONObject(res);
final String accessdb = jsonObject.getString("access");
final String passworddb = jsonObject.getString("password");
final String fullnamedb = jsonObject.getString("fullname");
final String branchdb = jsonObject.getString("branch");
final String sectiondb = jsonObject.getString("branch");
Log.e("Tag", accessdb);
} catch (JSONException e) {
e.printStackTrace();
}
}
Your requesting a JsonObject? 您正在请求一个JsonObject吗? You seem to have a grasp on StringRequest, so ill keep it simple. 您似乎对StringRequest有所了解,因此请保持简单。 Change your StringRequest
to a JsonObjectRequest
. 将您的StringRequest
更改为JsonObjectRequest
。
Problem : 问题:
As you can see in your logcat the response that you get from the server is success_access{"access":"PA001","password":"123","fullname":"ARCADE","branch":"HQ","section":"HQ"}
正如您在logcat中看到的那样,从服务器获得的响应是success_access{"access":"PA001","password":"123","fullname":"ARCADE","branch":"HQ","section":"HQ"}
First, this is not a valid JSON
. 首先,这不是有效的JSON
。 Also, that is the value of the response
variable. 同样,这就是response
变量的值。 Now, your response.equals("success_access")
will never return true, and hence the code control will never enter the if
block. 现在,您的response.equals("success_access")
将永远不会返回true,因此代码控件将永远不会进入if
块。
Solution : 解决方案:
Ideally, there should be no extra string like success_access
, insted your response should be a JSON
object ALWAYS containing one specified field (the result
feild for example). 理想情况下,不应有诸如success_access
类的多余字符串,否则您的响应应该是一个始终包含一个指定字段的JSON
对象(例如, result
字段)。 To show success, your JSON will look something like : 为了显示成功,您的JSON如下所示:
{
result : "success_access",
/* other parameters down here */
}
And in case of failure : 并且在失败的情况下:
{
result : "access_failed"
}
And then your code should convert the respose
string into a JSON
(your server code should make sure that it returns a valid JSON always) check for the value of the result
field and proceed further. 然后,您的代码应将respose
字符串转换为JSON
(您的服务器代码应确保其始终返回有效的JSON),以检查result
字段的值并继续进行操作。
Quick Fix : 快速解决 :
Change your code to : 将您的代码更改为:
....
Log.e(TAG, "Response is = " + response);
String result = response.replace("{.*}","");
String jsonString = response.replace(result, "");
if(result.equals("success_access")){
try {
JSONObject jsonObject = new JSONObject(jsonString);
....
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