Oracle SQL将行插入另一个表并更新数据

Question

In Oracle sql I can select a row into another table

insert into TableA (select * from TableB b where b.id = 2);

however, b.color = 'blue' and I want to update it to red before the row gets inserted into TableA without having to select each column from TableB, I want to select *.

Please do not mark this as answered in another question and give a link to answer that I can not use. TableA does not have an id that matches TableB.

Thank you

Answer 1

Insert your select into a temp table (which you will have to create) then update your temp table to red then insert it back to A

  INSERT INTO TEMP_TABLE 
  Select * from TableB b where b.id = 2

  Update temp_table
  Set color = 'Red'

  Insert into TableA (Select * from Temp_table)

Answer 2

"I want to select *"

does not make sense because you do NOT want to select *. If you did then you would want red not blue as the color.

You can hack around this using a trigger, eg

trigger BLAH 
before insert on A
for each row
begin
  :new.color := case when :new.color = 'blue' then 'red' else :new.color end;
end;

but man..I cannot tell you what a bad bad idea that would be.

Answer 3

I would suggest:

insert into TableA(col1, . . . , color, . . . coln)
     select . . . , (case when color = 'blue' then 'red' else color end), . . .
     from TableB b
     where b.id = 2;

Whether you like it or not, it is best practice to list all the columns both for the insert and the select , particularly for code that may be run more than one time.

If you find it too hard to list out the columns (using either a spreadsheet or SQL query), you can do the update afterwards :

insert into TableA
     select *
     from TableB b
     where b.id = 2;

update TableA
    set color = 'red'
    where color = 'blue' and id = 2;

This is approximate, because you might already have rows in the table, but it gives an idea.