[英]Chunk with eval=FALSE still evaluates on R Sweave
I'm working on some education manuals in spanish for a course, so I'm making a Sweave document with some chunks and I'm trying to make an example of an error message. 我正在用西班牙语编写一些教育手册,因此我正在制作带有一些块的Sweave文档,并尝试举一个错误消息的例子。 But first I need to show the souce of that error, so I'm using this code, since I don't want the code evaluating I'm using eval=FALSE:
但是首先我需要显示该错误的根源,所以我正在使用此代码,因为我不希望代码评估使用eval = FALSE:
<<eval=FALSE, error=TRUE,tidy=FALSE>>=
c(1,2 3)
#falta una coma
@
But the code is still evaluating and it's not letting me print the document, giving me this error message 但是代码仍在评估中,并且不允许我打印文档,从而给我此错误消息
(chunk 306) 5305:7: unexpected numeric constant
(块306)5305:7:意外的数字常量
Your code is being parsed, not evaluated. 您的代码正在解析,而不是评估。 If you have current versions of the
knitr
and evaluate
, this should result in a warning in the knitr
log, it won't stop the run. 如果您具有最新版本的
knitr
并evaluate
,这会在knitr
日志中导致警告,它不会停止运行。 I'm using knitr
1.16 and evaluate
0.10.1 and things are fine. 我正在使用
knitr
1.16并evaluate
0.10.1,一切正常。 See knitr: knitting chunks with parsing errors for a bit more on this. 有关更多信息,请参见knitr:编织带有解析错误的块 。
(BTW, I think you're using knitr
, not Sweave
. They're different. Sweave
can't handle this. If you really are using Sweave
, switch to knitr
. The switch is not hard, and brings a lot of benefits.) (顺便说一句,我认为您使用的是
knitr
而不是Sweave
。它们是不同的Sweave
无法处理此问题。如果您确实使用Sweave
,请切换到knitr
。切换并不困难,并且带来了很多好处。 )
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.