REGEX表达式C＃。 在引号外按空格分隔字符串

Question

I'm trying to define a regular expression for the Split function in order to obtain all substring split by a whitespace omitting those whitespaces that are into single quotation marks.

Example:

key1:value1 key2:'value2 value3'

i Need these separated values:

• key1:value1

• key2:'value2 value3'

I'm tried to perform this in different ways:

• Regex.Split(q, @"(\\s)^(' \\s ')").ToList();
• Regex.Split(q, @"(\\s)(^'. \\s. ')").ToList();
• Regex.Split(q, @"(?=.*\\s)").ToList();

What i am wrong with this code?

Could you please help me with this?

Thanks in advance

Answer 1

A working example:

(\\w+):(?:(\\w+)|'([^']+)')

(\w+)       # key: 1 or more word chars (captured)
:           # literal
(?:         # non-captured grouped alternatives
(\w+)       # value: 1 or more word chars (captured)
|           # or
'([^']+)'   # 1 or more not "'" enclosed by "'" (captured)
)           # end of group

Demo

Your try:

(\\s)^('\\s')

^ means beginning of line, \\s is a white-space characters. If you want to use the not-operator, this only works in a character class [^\\s] -> 1 character not a white-space.

Answer 2

Try following :

       static void Main(string[] args)
        {
            string input = "key1:value1 key2:'value2 value3'";
            string pattern = @"\s*(?'key'[^:]+):((?'value'[^'][^\s]+)|'(?'value'[^']+))";

            MatchCollection matches = Regex.Matches(input, pattern);
            foreach (Match match in matches)
            {
                Console.WriteLine("Key : '{0}', Value : '{1}'", match.Groups["key"].Value, match.Groups["value"].Value);
            }
            Console.ReadLine();
        }

Answer 3

    var st = "key1:value1 key2:'value2 value3'";
     var result = Regex.Matches(st, @"\w+:\w+|\w+:\'[^']+\'");

    foreach (var item in result)
        Console.WriteLine(item);

The result should be:

key1:value1
key2:'value2 value3'