Scapy库修改方法map（）

Question

I use the mapp method to go from list(str) to list(int), but when I call the scapy library. I do not get the same result.

I use python 2.7.13

print "E: {}".format(map(int, ['1', '2']))

return

E: [1, 2]

and

from scapy.all import *
print "E: {}".format(map(int, ['1', '2']))

return

E: <itertools.imap object at 0x0405E730

Answer 1

That's the risk you have when you import a module into your namespace in Python.

Here, you're using a development version of Scapy and that's a bug (you should not import Scapy's map() , which is the one provided by the six module, when importing Scapy). You should probably report it .

However, to avoid this, you should import Scapy in its own namespace. For example:

from scapy import all as scapy
scapy.IP() / scapy.ICMP()  # this will work
print "E: {}".format(map(int, ['1', '2']))  # this will display a list