简体   繁体   English

如何以功能方式实现数组连接?

[英]How to implement array joins in functional way?

I have a function that joins an array of objects with a conditional separator. 我有一个函数,它使用条件分隔符连接一个对象数组。

function getSegmentsLabel(segments) {
    var separator = '-';

    var segmentsLabel = '';
    var nextSeparator = '';
    _.forEach(segments, function(segment) {
        segmentsLabel += nextSeparator + segment.label;
        nextSeparator = segment.separatorUsed ? separator : ' ';
    });
    return segmentsLabel;
}

Usages: 用途:

var segments = [
    {label: 'First', separatorUsed: true},
    {label: 'Second', separatorUsed: false},
    {label: 'Third', separatorUsed: true},
    {label: 'Forth', separatorUsed: true}
];

getSegmentsLabel(segments); // Result: "First-Second Third-Forth"

How can the above getSegmentsLabel function be written in a purely functional way without mutating variables? 如何在不改变变量的情况下以纯函数方式编写上述getSegmentsLabel函数? We can use lodash functions. 我们可以使用lodash函数。

recursion 递归

or instead of map/reduce/join, you can use direct recursion – the benefit here is that we don't iterate thru the collection multiple times to compute the result – oh and the program is really small so it's easy to digest 或者代替map / reduce / join,你可以使用直接递归 - 这里的好处是我们不会多次迭代通过集合来计算结果 - 哦,程序非常小,所以很容易消化

be careful of stack overflows in javascript tho; 小心javascript中的堆栈溢出; relevant: How do I replace while loops with a functional programming alternative without tail call optimization? 相关: 如何在没有尾调优化的情况下使用函数式编程替换while循环?

 var segments = [ {label: 'First', separatorUsed: true}, {label: 'Second', separatorUsed: false}, {label: 'Third', separatorUsed: true}, {label: 'Forth', separatorUsed: true} ]; const main = ([x,...xs]) => x === undefined ? '' : xs.length === 0 ? x.label : x.label + (x.separatorUsed ? '-' : ' ') + main (xs) console.log (main (segments)) // First-Second Third-Forth 


functional programming 函数式编程

that last implementation of our function is awfully specific - functional programming isn't just about using map and reduce, it's about making meaningful abstractions and writing generic procedures that can easily be reused 我们函数的最后一个实现是非常具体的 - 函数式编程不只是使用map和reduce,它是关于进行有意义的抽象和编写可以轻松重用的通用过程

this example is intentionally very different from your original code with the hope that it will get you to think about programs in a different way – if this stuff interests you, as a follow up to this post, you could start reading about monoids . 这个例子与你的原始代码有意无异,希望它能让你以不同的方式思考程序 - 如果这些东西让你感兴趣,作为这篇文章的后续内容,你可以开始阅读关于monoids的内容

by writing our program this way, we've represented this idea of "joinable pieces of text with conditional separators" in a generic text module that could be used in any other program – writers can create units of text using Text.make and combine them using Text.concat 通过这种方式编写我们的程序,我们在一个通用文本模块中表示了“带条件分隔符的可连接文本”的概念,可以在任何其他程序中使用 - 编写者可以使用Text.make创建文本单元并将它们组合在一起使用Text.concat

another advantage in this program is the separator is parameter-controlled 该程序的另一个优点是分离器是参数控制的

 // type Text :: { text :: String, separator :: String } const Text = { // Text.make :: (String × String?) -> Text make: (text, separator = '') => ({ type: 'text', text, separator }), // Text.empty :: Text empty: () => Text.make (''), // Text.isEmpty :: Text -> Boolean isEmpty: l => l.text === '', // Text.concat :: (Text × Text) -> Text concat: (x,y) => Text.isEmpty (y) ? x : Text.make (x.text + x.separator + y.text, y.separator), // Text.concatAll :: [Text] -> Text concatAll: ts => ts.reduce (Text.concat, Text.empty ()) } // main :: [Text] -> String const main = xs => Text.concatAll (xs) .text // data :: [Text] const data = [ Text.make ('First', '-'), Text.make ('Second', ' '), Text.make ('Third', '-'), Text.make ('Fourth', '-') ] console.log (main (data)) // First-Second Third-Fourth 

You can use map() method that will return new array and then join() to get string form that array. 您可以使用将返回新数组的map()方法,然后使用join()来获取该数组的字符串形式。

 var segments = [ {label: 'First', separatorUsed: true}, {label: 'Second', separatorUsed: false}, {label: 'Third', separatorUsed: true}, {label: 'Forth', separatorUsed: true} ]; function getSegmentsLabel(segments) { return segments.map(function(e, i) { return e.label + (i != segments.length - 1 ? (e.separatorUsed ? '-' : ' ') : '') }).join('') } console.log(getSegmentsLabel(segments)); 

You could use an array for the separators and decide, if a spacer, a dash or no separator for strings at the end. 你可以使用一个数组作为分隔符,并决定,如果是一个spacer,破折号或者没有字符串的分隔符。

 const separators = [' ', '', '-']; var getSegmentsLabel = array => array .map(({ label, separatorUsed }, i, a) => label + separators[2 * separatorUsed - (i + 1 === a.length)]) .join(''); var segments = [{ label: 'First', separatorUsed: true }, { label: 'Second', separatorUsed: false }, { label: 'Third', separatorUsed: true }, { label: 'Forth', separatorUsed: true }]; console.log(getSegmentsLabel(segments)); 

Here I separate out the functions: 在这里,我将功能分开:

// buildSeparatedStr returns a function that can be used
// in the reducer, employing a template literal as the returned value
const buildSeparatedStr = (sep) => (p, c, i, a) => {
  const separator = !c.separatorUsed || i === a.length - 1 ? ' ' : sep;
  return `${p}${c.label}${separator}`;
}

// Accept an array and the buildSeparatedStr function
const getSegmentsLabel = (arr, fn) => arr.reduce(fn, '');

// Pass in the array, and the buildSeparatedStr function with
// the separator
const str = getSegmentsLabel(segments, buildSeparatedStr('-'));

DEMO DEMO

It's better to use reduceRight instead of map in this case: 在这种情况下,最好使用reduceRight而不是map

 const segments = [ {label: 'First', separatorUsed: true}, {label: 'Second', separatorUsed: false}, {label: 'Third', separatorUsed: true}, {label: 'Forth', separatorUsed: true} ]; const getSegmentsLabel = segments => segments.slice(0, -1).reduceRight((segmentsLabel, {label, separatorUsed}) => label + (separatorUsed ? "-" : " ") + segmentsLabel, segments[segments.length - 1].label); console.log(JSON.stringify(getSegmentsLabel(segments))); 

As you can see, it's better to iterate through the array from right to left. 如您所见,最好从右到左遍历数组。


Here's a more efficient version of the program, although it uses mutation: 这是一个更高效的程序版本,虽然它使用了变异:

 const segments = [ {label: 'First', separatorUsed: true}, {label: 'Second', separatorUsed: false}, {label: 'Third', separatorUsed: true}, {label: 'Forth', separatorUsed: true} ]; const reduceRight = (xs, step, base) => { const x = xs.pop(), result = xs.reduceRight(step, base(x)); return xs.push(x), result; }; const getSegmentsLabel = segments => reduceRight(segments, (segmentsLabel, {label, separatorUsed}) => label + (separatorUsed ? "-" : " ") + segmentsLabel, ({label}) => label); console.log(JSON.stringify(getSegmentsLabel(segments))); 

It's not purely functional but if we treat reduceRight as a black box then you can define getSegmentsLabel in a purely functional way. 它不是纯粹的功能,但如果我们将reduceRight视为黑盒子,那么你可以用纯粹的功能方式定义getSegmentsLabel

 const segments = [ {label: 'First', separatorUsed: true}, {label: 'Second', separatorUsed: false}, {label: 'Third', separatorUsed: true}, {label: 'Forth', separatorUsed: true} ]; const segmentsLabel = segments.reduce((label, segment, i, arr) => { const separator = (i === arr.length - 1) ? '' : (segment.separatorUsed) ? '-' : ' '; return label + segment.label + separator; }, ''); console.log(segmentsLabel); 

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM