[英]int doesn't work in def within regular expression in python
I need to write function which takes a count and a string and return a list of all of the words in the string that are count word characters long or longer. 我需要编写一个函数,该函数需要一个计数和一个字符串,并返回该字符串中所有字的字符长度或更长的列表。
My function is: 我的职能是:
import re
def find_words(count, a_str):
count = int(count)
return re.findall(r'\w{},'.format(int(count)), a_str)
But it doesn't work, it is return empty list: 但这不起作用,它返回空列表:
Example: 例:
find_words(4, "dog, cat, baby, balloon, me")
Should return: 应该返回:
['baby', 'balloon']
The regex isn't correct. 正则表达式不正确。 The
{}
is interpreted as placeholder for format
, but you want it to be the regexs' {}
which specifies the number of repeats. {}
被解释为format
占位符,但您希望它是正则表达式的{}
,用于指定重复次数。 You need to use r'\\w{{{}}}'
here. 您需要在此处使用
r'\\w{{{}}}'
。 Observe the difference: 观察差异:
>>> r'\w{},'.format(4)
'\\w4,'
>>> r'\w{{{},}}'.format(4)
'\\w{4,}'
And then it works correctly: 然后它可以正常工作:
import re
def find_words(count, a_str):
count = int(count)
return re.findall(r'\w{{{},}}'.format(count), a_str)
>>> find_words(4, "dog, cat, baby, balloon, me")
['baby', 'balloon']
Why RegExp? 为什么选择RegExp?
>>> string = "dog, cat, baby, balloon, me"
>>> [word for word in string.split(', ') if len(word) >= 4]
['baby', 'balloon']
So function could be something like follow: 因此功能可能如下所示:
>>> def find_words(count, a_str):
... return [word for word in a_str.split(', ') if len(word) >= count]
...
>>> find_words(4, 'dog, cat, baby, balloon, me')
['baby', 'balloon']
You can try this: 您可以尝试以下方法:
def find_words(count, a_str):
s = [re.findall("\w{"+str(count)+",}", i) for i in ["dog, cat, baby, balloon, me"]]
return s[0]
print(find_words(4, ["dog, cat, baby, balloon, me"]))
Output: 输出:
['baby', 'balloon']
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