检查列表的元素是否是另一个列表的元素的子集

Question

Here I am trying to check whether elements of 'b' that are [1,3],[1,5],[3,7],[5,7],[6,9],[8,10] are subsets of elements of 'a' that are [1,3,5,7] and [6,8,9,10]. If any element of b is subset of any element of a then it gets removed from b.

     a = [[1, 3, 5, 7],[6, 8, 9, 10]]
     b = [[1, 3], [1, 5],[10, 11],[6, 9],[8, 10]]

If any element of 'b' is subset of any element of 'a' then it gets removed from b. That means the new b should be :-

     b = [[10,11]]

Answer 1

如果要进行集合操作，请使用python的集合数据类型，该数据类型具有issubset()方法。

b = [x for x in b if not any(set(x).issubset(y) for y in a)]