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Android-使用asynctask将JSON转换为Textview

[英]Android - JSON to textview using asynctask

I'm creating a Movie Catalog app. 我正在创建一个电影目录应用程序。 I have a problem, I want to get detailmovie (from the movie id). 我有一个问题,我想获取detailmovie (从电影ID)。 I send the id movie from the listview I get, I already created the DetailActivity and I test get the movie title but it doesn't work. 我从获取的listview发送ID电影,我已经创建了DetailActivity并测试了电影标题,但是它不起作用。 What can i do? 我能做什么?

here's my code 这是我的代码

public class DetailActivity extends AppCompatActivity {

TextView txt_title,txt_detail,txt_rate;
ImageView img_posterd;

public static String API_KEY = "f00e74c69ff0512cf9e5bf128569f****";

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_detail);

    Intent i = getIntent();
    String idmov = i.getStringExtra("idmovie");

    String url = "https://api.themoviedb.org/3/movie/"+idmov+"?api_key="+API_KEY+"&language=en-US";
    txt_title = (TextView) findViewById(R.id.tv_title_detail);
    new GetMovieTask(txt_title).execute(url);

}

private class GetMovieTask extends AsyncTask<String, Void, String>{

    TextView txt_title;

    public GetMovieTask(TextView txt_title) {
        this.txt_title = txt_title;

    }

    @Override
    protected String doInBackground(String... strings) {
        String title = "UNDEFINED";

        try {
            URL url = new URL(strings[0]);
            HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();

            JSONObject object = new JSONObject();
            title = object.getString("original_title");

            urlConnection.disconnect();
            Log.d("titlenya", title);

        }catch (IOException | JSONException e){
            e.printStackTrace();
        }
        return title;

    }

    @Override
    protected void onPostExecute(String original_title) {
        txt_title.setText("Ti : " +original_title);
    }
}

}

I'm using themoviedb API. 我正在使用themoviedb API。 loopj library for the listview. listj的loopj库。

You can not take JSON like that. 您不能像这样使用JSON。 And hence your code throws this 因此,您的代码抛出了这个

08-26 23:26:27.871 20145-20862/? W/System.err: org.json.JSONException: No value for original_title

first you have to read response from the webservice in the form of string and then use JSONObject = new JSONObject(string); 首先,您必须以字符串形式读取来自Web服务的响应,然后使用JSONObject = new JSONObject(string); to convert it to a JSONObject. 将其转换为JSONObject。 For example 例如

try {
    URL url = new URL(strings[0]);
    HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();

    int responseCode = urlConnection.getResponseCode();
    Log.i(TAG, "POST Response Code: " + responseCode);

    //Takes data only if response from WebService is OK
    if (responseCode == HttpURLConnection.HTTP_OK) {
        BufferedReader in = new BufferedReader(new InputStreamReader(urlConnection.getInputStream()));
        String inputLine;
        StringBuilder response = new StringBuilder();

        //Stores input line by line in response
        while ((inputLine = in.readLine()) != null) {
            response.append(inputLine);
        }
        in.close();

        //get data in JSON
        JSONObject object = new JSONObject(response.toString());
        title = object.getString("original_title");

        urlConnection.disconnect();
        Log.d("titlenya", title);

    }
} catch (IOException | JSONException e) {
    e.printStackTrace();
}

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