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不同类别中的不同类型的数据

[英]Different types of data in different classes

public class Node
{
    Node next, child;
    String data;

    Node()
    {
        this(null);
    }

    Node(String s)
    {
        data = s;
        next = child = null;
    }

    Node get(int n)
    {
        Node x = this;
        for(int i=0; i<n; i++)
            x = x.next;
        return x;
    }

    int length()
    {
        int l;
        Node x = this;
        for(l=0; x!=null; l++)
            x = x.next;
        return l;
    }

    void concat(Node b)
    {
        Node a = this.get(this.length() - 1);
        a.next = b;
    }

    void traverse()
    {
        Node x = this;
        while(x!=null)
        {
            System.out.println(x.data);
            x = x.next;
        }
    }
}

class IntegerNode extends Node
{
    int data;

    IntegerNode(int x)
    {
        super();
        data = x;
    }
}

Is there any way I can have different types of data in the two classes so that I can use the IntegerNode class with numbers and the Node class with Strings? 有什么办法可以在两个类中使用不同类型的data ,以便可以将IntegerNode类与数字一起使用,将Node类与字符串一起使用?

Example: 例:

public class Test
{
    public static void main(String args[])
    {
        IntegerNode x = new IntegerNode(9);
        IntegerNode y = new IntegerNode(10);
        x.concat(y);
        x.concat(new Node("End"));
        x.traverse();
    }
}

Right now, this is the output I'm getting: null null End 现在,这是我得到的输出: null null End

Any explanation would help. 任何解释都会有所帮助。 Thank you in advance. 先感谢您。

The default way would be to use generics . 默认方式是使用泛型

Like: 喜欢:

public class Node <T> {
  private final T data;

  public Node(T data) { this.data = data; }

to then use like: 然后使用像:

Node<Integer> intNode = new Node<>(5);
Node<String> stringNode = new Node<>("five");

Please note: the above is how you solve such problems in Java. 请注意: 以上是解决Java中此类问题的方法。 Using inheritance here would a rather wrong approach. 在这里使用继承将是一个相当错误的方法。 Unless you would really find a good reason to be able to concat() nodes with different data. 除非您真的找到一个很好的理由能够将不同数据的concat()节点连接起来。 As my solution fully "separates" a Node<Integer> form a Node<String> . 当我的解决方案完全“分离” Node<Integer>形成Node<String> And yes, that means that users could create Node<Whatever> objects at any time. 是的,这意味着用户可以随时创建Node<Whatever>对象。

Thus: if you really want only Integer and String data nodes - then you would actually do the following: 因此:如果您只需要 Integer和String数据节点,那么您实际上将执行以下操作:

  • make the base Node class hold data as Object 使基本Node类将数据保存为Object
  • make the base class abstract 使基类抽象
  • create two specific subclasses for Integer/String, as outlined in the other answer 如另一个答案所述,为Integer / String创建两个特定的子类

But the question would be: what happens when you decide next week that you want Float and Double, too. 但是问题是:当您下周决定也要Float和Double时会发生什么。 And maybe Dates? 也许日期? Then you would have to create new subclasses each time. 然后,您每次都必须创建新的子类。 Leading to a lot of duplicated code. 导致很多重复的代码。

So the real answer here: really think your requirements through. 因此,这里的真正答案是:认真考虑您的要求。 Understand what is exactly that you want to build. 了解您到底要构建什么。 And then see which path you should take. 然后查看您应该走哪条路。

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