PHP Regex将重复的字符减少为单个实例

Question

I want to rid a text for repeated exclamation marks (!!!), question marks (??) or full stops (....) and replace them with a single instance of themselves. So I need "one preg_replace to rule them all" basically.

I currently have three separate patterns being executed:

preg_replace("/[!]{2,}/","!", $str);
preg_replace("/[?]{2,}/","?", $str);
preg_replace("/[.]{2,}/",".", $str);

Is there a way to replace the found character with a single instance of itself using just one regex pattern?

I need to turn:

Ok!!!
Really????
I guess.....

into:

Ok!
Really?
I guess.

With one regex pattern.

Answer 1

Use a capturing group with a backreference:

([?!.])\1+

Replace with $1 .

See the regex demo.

Details

• ([?!.]) - matches and captures into Group 1 a single char: ? , ! or .
• \\1+ - matches one or more instances of the content captured into Group 1.

PHP demo :

$str = "Ok!!!\nReally????\nI guess.....";
$res = preg_replace('/([?!.])\1+/', '$1', $str);
echo $res;

Results:

Ok!
Really?
I guess.

Answer 2

Just for completion, I thought I'd post my own answer based on my original code after viewing the answer given by another.

 pattern ([!?.]){2,}

 preg_replace('/([!?.]){2,}/','$1', $str);

This pattern also seems to work fine.