启动嵌入式Tomcat并从命令行打开浏览器

Question

I have a java web app that uses embedded Tomcat. I'd like users to open it by executing a single .bat file (Windows).

I use this line for starting Tomcat:

java -cp "%cd%\apache-tomcat-8.0.8-embed\*;%cd%" Main

(main.java starts Tomcat) and if I put this line next, it won't be executed unless I manually stop Tomcat (Ctrl+C):

start http://127.0.0.1:8080/

If I open the browser first, and start Tomcat after that, then the users will see an error message from the browser for some seconds (while tomcat starts), and they'll panic ;)

Is there a way to return the focus to the script once Tomcat has started?, or some other workaround for this?

In other similar threads, I saw that they could accomplish this, but they were starting tomcat by executing a Tomcat.exe file, which is not my case, since I need to use this embedded version of Tomcat, and start it the way I'm starting it.

The best case scenario would be if I could display a temporary page saying "please wait..." while Tomcat is starting, and when it's done, show my app's initial page ( http://127.0.0.1:8080/ )

Any help will be really appreciated

Answer 1

If I understand you correctly, you can simply start java with the start command without interrupting the execution flow of the script. In other words, the script doesn't wait for the java process to end before executing the next command.

start java -cp "%cd%\apache-tomcat-8.0.8-embed\*;%cd%" Main