如何管理多个节点项目？

Question

We are using 3 different node projects: Project 1 , Project 2 and Project 3 using react and webpack . All 3 projects are hosted in 3 different repositories.

Project 1 and Project 2 are independent but Project 3 needs zip file of both Project 1 and Project 2 and are put in Project 3 as devDependencies(node_modules).

Now the problem comes when we need to make changes in Project 1 or Project 2 so that the new zip file can be used in Project 3 .

For debugging, we need to change the code in Project 1 or Project 2 and then build a zip using npm pack and then update that zip in Project 3 and stop the build of Project 3 and then uninstall and install that zip again and then run the Project 3 again.

The other, a little bit faster, a solution is to build Project 1 or Project 2 using npm pack and then copy the lib file generated and then copy that in /node_modules/Project 1(or2)/lib folder in Project 3 running instance.

Is there a better or faster or more convenient way to do manage all these projects?

Please don't suggest lerna . Lerna is a great tool but it needs change in architecture which is not feasible.

Answer 1

Can't you publish project1 and project2 to npm?

npm publish project1
npm publish project2

Makes these projects devDependencies in project3.

Then just an npm install in project3 will get the lastest project1 and project2.

If privacy is a concern, can't you get a private npm repo? Yeah it costs.

Alternatively, you could host your own npm repo on your own server?

Answer 2

I would put them all in one repo. Then you are guaranteed to know where all the projects are relative to each other. Each project is just a sub-folder, and has it's own package.json as it does now.

You just need some scripts that will do the zipping and copying to the right place in each project.

I would make those scripts run from the top level of the project (which has it's own package.json , in the scripts folder. Some adjustments of .gitignore to stop zip files getting checked in and you should be good.