SQL ACCESS - 选择max（日期）和相应的值

Question

How can I get the corresponding value of MAX(date). Access it returns me an error when I select directly the column with the specified value.

For example, I want to be shown only the line from the image.

Thank you.

Answer 1

Use TOP and ORDER BY :

select top 1 *
from t
order by date desc;

EDIT:

If you want the last date per code, then use a correlated subquery:

select t.*
from t
where t.date = (select max(t2.date) from t t2 where t2.code = t.code);

Answer 2

select * from tblName where DocumentDate in (select max(DocumentDate ) from tblName)

请用这个

Answer 3

You mast creat the join query. For example find MAX(DocumentDate) :

SELECT DocumentNumber, Code, SoldPuncte, DocumentDate   
from yourTable a inner join 
          (SELECT DocumentNumber, Code, SoldPuncte, MAX(DocumentDate) as 
          DocumentDate 
          from yourTable group by DocumentNumber) b 
on a.DocumentNumber=b.DocumentNumber and a.DocumentDate = b.DocumentDate

Answer 4

If you need last date per code then try this one

SELECT Code, MAX(DocumentDate)
FROM table
GROUP BY Code