在bash shell中的文件中每行打印3个字符

Question

I was solving one problem from one site, question is as follows:

"Given N lines of input in a file, print the 3rd character from each line as a new line of output. It is guaranteed that each of the n lines of input will have a 3rd character."

So to solve the problem I have written a command

while read -r line
do 
      echo ${line:2:1}
done < sample.txt

Content in "sample.txt" is :

C.B - Cantonment Board/Cantonment
C.M.C – City Municipal Council
C.T – Census Town
E.O – Estate Office
G.P - Gram Panchayat
I.N.A – Industrial Notified Area
I.T.S - Industrial Township
M – Municipality
M.B – Municipal Board
M.C – Municipal Committee

I am getting output as follows:

B
M
T
O
P
N
T
â
B
C

According to the site, the answer should be:

B
M
T
O
P
N
T
в
B
C

Please not that 3rd last output is "в" and I am getting "â" I am new to the ascii, uts-8 conversion so not aware if this has any relation .

What should be change in the code to bring this answer?

Answer 1

这可以通过简单的cut调用来完成：

$ cut -c3 sample.txt

Answer 2

使用awk ：使用FS=""列更改为字符

awk -vFS="" '{print $3}' file