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SQL查询返回按日期排序的SUMS和计数

[英]SQL Query to Return SUMS and Count Ordered by Date

I have the two following tables: 我有以下两个表:

Table 1 Table 2 表1 表2

What I want to do is to have a query that returns a SUM of PIT_VALORTOTAL, PIT_VOLUME and a count of PED_IDPESSOA per date. 我想做的是有一个查询,该查询返回每个日期的总和为PIT_VALORTOTAL,PIT_VOLUME和PED_IDPESSOA。 What I have so far is: 到目前为止,我有:

SELECT SUM(PIT_VALORTOTAL) AS VALORTOTAL, SUM(PIT_VOLUME) AS VOLUME, COUNT(DISTINCT PED_IDPESSOA) AS PESSOA FROM PEDIDOS_ITENS INNER JOIN PEDIDOS ON PIT_IDPEDIDO = PED_ID;

And it returns the sums and the count correctly, but I don't have a clue on how to get these seperatly per dates. 它正确地返回了总和和计数,但是我不知道如何分别获取每个日期的线索。 So what I have is this: 所以我有这个:

VALORTOTAL       | VOLUME             | PESSOA  |
49783.2000000    |       679780.360000|   11    |

And what I want is something like: 我想要的是这样的:

| DATE      | VALORTOTAL    | VOLUME     | PESSOA  |
| 2017-09-03| 1012,00       |       1209 |   12    |
| 2017-09-03| 2012,00       |       1450 |   10    |
| 2017-09-03| 3016,00       |       2500 |   20    | 
| 2017-09-03| 3016,00       |       3200 |   5     |
| 2017-09-03| 2016,00       |       4000 |   9     |

You just need group by : 您只需要按group by

SELECT PED_DATA, SUM(PIT_VALORTOTAL) AS VALORTOTAL, SUM(PIT_VOLUME) AS VOLUME,
       COUNT(DISTINCT PED_IDPESSOA) AS PESSOA
FROM PEDIDOS_ITENS pi INNER JOIN
     PEDIDOS p
     ON PIT_IDPEDIDO = PED_ID
GROUP BY PED_DATA
ORDER BY PED_DATA

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