清单中的Python Append字典

Question

[{'Size': 0.0}, {'Size': 19.391637}]
[{'ContainerID': '9bcb46615a',
  'MemUsage': 2.85546875,
  'MaxMem': 1.9522056579589844},
 {'ContainerID': '9aadddf8e0',
  'MemUsage': 17.203125,
  'MaxMem': 1.9522056579589844}]

I have the two lists with dicts above, how can I append the first to the second such that:

[{'ContainerID': '9bcb46615a',
  'MemUsage': 2.85546875,
  'MaxMem': 1.9522056579589844,
  'Size': 0.0},
 {'ContainerID': '9aadddf8e0',
  'MemUsage': 17.203125,
  'MaxMem': 1.9522056579589844,
  'Size': 19.391637}]

Answer 1

If you are using Python3:

s1 = [{'Size': 0.0}, {'Size': 19.391637}]
s2 = [{'ContainerID': '9bcb46615a', 'MemUsage': 2.85546875, 'MaxMem': 1.9522056579589844}, {'ContainerID': '9aadddf8e0', 'MemUsage': 17.203125, 'MaxMem': 1.9522056579589844}]

final_dict = [{**a, **b} for a, b in zip(s2, s1)]

Output:

[{'MemUsage': 2.85546875, 'ContainerID': '9bcb46615a', 'MaxMem': 1.9522056579589844, 'Size': 0.0}, {'MemUsage': 17.203125, 'ContainerID': '9aadddf8e0', 'MaxMem': 1.9522056579589844, 'Size': 19.391637}]

Explanation: the ** is called dictionary unpacking. It splits the contents of the dictionary into its respective key-value pairs and allows you to merge them into one dictionary.

If you are using Python2:

final_data = [dict(a.items()+b.items()) for a, b in zip(s2, s1)]

Output:

[{'Size': 0.0, 'MemUsage': 2.85546875, 'ContainerID': '9bcb46615a', 'MaxMem': 1.9522056579589844}, {'Size': 19.391637, 'MemUsage': 17.203125, 'ContainerID': '9aadddf8e0', 'MaxMem': 1.9522056579589844}]

Answer 2

Doing it in-place ( l1 , l2 are your lists):

for d1, d2 in zip(l1, l2):
    d2.update(d1)