[英]How to build query WHERE X OR HAVING Y
My data is a parent table named sales
and a child table named sale_lines
. 我的数据是一个名为
sales
的父表和一个名为sale_lines
的子表。 I'd like to select all records from the sales
table where sale.customer_id=X
OR SUM(sale_lines.total)>=Y
. 我想从
sales
表中选择所有记录,其中sale.customer_id=X
或SUM(sale_lines.total)>=Y
The customer_id
condition will go in the WHERE
clause and it makes sense to have the SUM(sale_lines.total)>Y
in the HAVING
clause. customer_id
条件将放在WHERE
子句中,并且在HAVING
子句中具有SUM(sale_lines.total)>Y
是有意义的。 My problem is how to have a logical OR
between the WHERE
and HAVING
clauses. 我的问题是如何在
WHERE
和HAVING
子句之间进行逻辑OR
。 Is this possible? 这可能吗? If so, how?
如果是这样,怎么办?
I know how to do this with a sub-query, but I'm trying to develop an automated query generation solution and I'd like to avoid the complexity of dealing with sub-queries. 我知道如何使用子查询来执行此操作,但是我正在尝试开发一种自动查询生成解决方案,并且我想避免处理子查询的复杂性。
You need to do this in the having
clause: 您需要在
having
子句中执行此操作:
select . . .
from . . .
group by s.customer_id, . . .
having s.customer_id = X or sum(s.total) > Y;
The query might look like: 查询可能看起来像:
select s.customer_id, sum(s.total)
from sales s
group by s.customer_id
having s.customer_id = X or sum(s.total) > Y;
Because of the or
, you cannot filter before aggregation. 由于存在
or
,因此无法在聚合之前进行过滤。
Actually, if you want the records from the sales table (and not the aggregations), then something like this is appropriate: 实际上,如果您希望从sales表中获得记录(而不是聚合),则可以使用如下所示的方法:
select s.*
from sales s
where s.customer_id = X or
s.customer_id in (select s2.customer_id
from sales s2
group by s2.customer_id
having sum(s2.total) > Y
);
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