[英]PHP getting HTTP error 500
I want to retrieve data from the hosting but it returns me a HTTP error 500 when I tried to test my php. 我想从托管中检索数据,但是当我尝试测试php时,它返回了HTTP错误500。
This is my php code: 这是我的PHP代码:
/**
* Getting all stock
*/
public function getstockdesc() {
$con = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD,DB_DATABASE);
$result = mysqli_query($con,"select * FROM stockdesc");
return $result;
}
This is the for sync into android sqllite: 这是用于同步到android sqllite的:
<?php
include_once 'db_functions.php';
$db = new DB_Functions();
$stockdesc = $db->getstockdesc();
$a = array();
$b = array();
if($stockdesc != false){
while($row = mysql_fetch_array($stockdesc)){
$b["stockdescId"] = $row["stockdescId"];
$b["stockdesc"] = $row["stockdesc"];
$b["itemCode"] = $row["itemCode"];
array_push($a,$b);
}
echo json_encode($a);
return $b;
}
else{
return false;
}
?>
HOLY MOLY, I got the answers right now thx. 圣莫莉,我现在得到答案了。
Recently using: 最近使用:
mysql_fetch_array() mysql_fetch_array()
Need to change to 需要更改为
mysqli_fetch_array() mysqli_fetch_array()
My bad not paying attention! 我不好不注意!
Thanks Nipun Tyagi for finding my typo :D! 感谢Nipun Tyagi找到我的错字:D!
Use the following to see the actual error: 使用以下命令查看实际错误:
error_reporting(E_ALL);
ini_set('display_errors', 1);
Place it in the beginning of the code ;) 将其放在代码的开头;)
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