通过检查列表是否包含其他列表的元素进行过滤。 怎么做？

Question

I can't figure out how to correctly create the first return . It would work like this but the problem is searchtestarrayone always has a different length and it can be pretty large. Started my journey with Swift a few weeks ago, so there might be stupid things in the code below and the answer can be obvious, forgive me.

func updateSearchResults(for searchController: UISearchController){

   if let searchText = searchController.searchBar.text, !searchText.isEmpty {          
       transformSearchResult()

       filteredBusStopsArray = busStopsArray.filter { (busstop : BusStop)  in

           if !searchtestarrayone.isEmpty{
              return busstop.stopName.lowercased().contains(searchtestarrayone[0]) || busstop.stopName.lowercased().contains(searchtestarrayone[1])
           }
           else{
               return  busstop.stopName.lowercased().contains(searchText.lowercased())
           }

Looking for some tips. Best regards.

Answer 1

You should map busStopsArray to only include lowercased stop names and filter it with searchtestarrayone .

filteredBusStopsArray = (busStopsArray.map { $0.stopName.lowercased() }).filter {
    searchtestarrayone.contains($0)
}

Answer 2

If you want to return whether busstop.stopName contains any of the values of searchtestarrayone 's values, you can use contains.where .

if !searchtestarrayone.isEmpty{
    return searchTestArrayOne.contains(where: {busStop.stopName.lowercased().contains($0)})
}

This will return true if any of the elements of searchTestArrayOne are contained in busStop.stopName and false otherwise. contains(where:) also exits early, as soon as it finds the first element matching the closure, so he full search array is only iterated through if there is no match.

Please also make sure that you conform to the Swift naming convention, which is lower-camelCase for function and variable names.