解析其余API的json响应并删除某些jsonObjects-JAVA

Question

I have a json file as below which I am getting as a response from rest API:

{
  "label": " MARA LEYZIN",
  "ClassCode": "PROFESSIONAL",
  "actvFlg": "A",
  "name": "MARA LEYZIN",
  "Typ": {
    "label": "C_TYP_LU",
    "TypCode": "PROFESSIONAL  "
  },
  "Address": {
    "link": [],
    "firstRecord": 1,
    "pageSize": 10,
    "searchToken": "multi",
    "item": [
      {
        "label": "Address",
        "addrTypFk": {
          "label": "C_ADDRESS_TYPE_LU",
          "addrTypCd": "INDUSTRY",
          "addrTypDesc": "Industry"
        }
}
]
}

I am trying to parse this in Java and to remove some unwanted json objects. Like I want the following string to be replaced by blank:

"link": [],
    "firstRecord": 1,
    "pageSize": 10,
    "searchToken": "multi",
    "item":

To achieve this I am trying the following approach:

String jsonStr = new String(Files.readAllBytes(Paths.get(inputFile)));
System.out.println(jsonStr);
jsonStr.replaceAll("link", "");

But it is not replacing the required string with blanks. Please help me in this.

Answer 1

string object is immutable , so basically if do you want to replace something
System.out.println(jsonStr.replaceAll("link", "")); this will print the replaced string but it will not affect the original string, however if you do this

jsonStr=jsonStr.replaceAll("link", "");

System.out.println(jsonStr); this will print the replaced string

Answer 2

First of all: Your JSON is not validate. You're missing a closing curly bracket at the end of it.

{
"label": " MARA LEYZIN",
"ClassCode": "PROFESSIONAL",
"actvFlg": "A",
"name": "MARA LEYZIN",
"Typ": {
    "label": "C_TYP_LU",
    "TypCode": "PROFESSIONAL  "
},
"Address": {
    "link": [],
    "firstRecord": 1,
    "pageSize": 10,
    "searchToken": "multi",
    "item": [{
        "label": "Address",
        "addrTypFk": {
            "label": "C_ADDRESS_TYPE_LU",
            "addrTypCd": "INDUSTRY",
            "addrTypDesc": "Industry"
        }
    }]
}

}

Second of all you should just change order of your commands to this:

jsonStr.replaceAll("link", "");
System.out.println(jsonStr);

Important addition : And I would suggest you to use org.json library or even better JACKSON to parse JSON files.

Here's tutorial how to use jackson and it's my warmest suggestion. You will save a lot of time and you can do whatever you like.