Oracle SQL中的日期格式

Question

Below is my sample tables and the expected output and the corresponding query that I have return. I am running into DATE FORMAT ISSUES, When I try to get the Earliest date record from PROV table. Please Let me know if this is not clear

select *
from   beau_prov beau
       join provi prov
            on  trim(beau.no) = trim(prov.prov_no)
where  prov.ins_dt =
       ( select min(ins_dt)
         from   provi prov
         where  trim(beau.no) = trim(prov.no)
         and    beau.year = to_char(to_date(ins_dt, 'MM/DD/YYYY HH:MI:SS PM', 'YYYY'), 'YYYY') )

BEAU

----------------------      
NAME |  NO    | YEAR |
----------------------
CAR  |  1234  | 2013 |
AUTO |  4356  | 2013 |

PROV

-----------------------------------------------     
NO   |NUMBER | NAME  | INS_DT                 |
-----------------------------------------------
1234 |  987  |  ZZ   | 7/13/2013 11:36:05 PM  | 
1234 |  456  |  ZZ   | 12/31/2013 10:34:45 PM | 

RESULT

---------------------------------------
NAME |  NO    | YEAR |  NUMBER | NAME |
---------------------------------------
CAR  |  1234  | 2013 |  987    | ZZ   |

Answer 1

If INS_DT is an Oracle date , then you can just insert it into another date column as it is.

The formatting you are seeing is applied by the client application and is not part of the date value itself.

If it's supplied to your procedure as a string, then you would need to convert it to a date using to_date(ins_dt,'DD/MM/YYYY HH:MI:SS PM') .

If INS_DT is an Oracle date and BEAU_PROV.YEAR is a string containing a 4-digit year, then you can join them using:

and beau.year = to_char(ins_dt,'YYYY')