如何使用清单 <string> 作为字典中的键

Question

I'm trying to create a dictionary where the keys will be the elements in a pre-existing List<string> and the values will be List<List<string>> like this:

List<string> newDictKeys = new List<string>(new []{"12323","432234","45345435"});
List<string> listVal1 = new List<string>(new []{"dfgdfg","asdfds","wertert"});
List<string> listVal2 = new List<string>(new []{"ZCxzcx","xcvbcvb","gfhjfgj"});

List<List<string>> dictVals = new List<List<string>>();

Dictionary<string,List<List<string>> dict = new  Dictionary<string,List<List<string>>();

Is there any simple, elegant way to do this?

EDIT

Essentially this would be the mapping:

"12323" -> ["dfgdfg","ZCxzcx"]
"432234" -> ["asdfds","xcvbcvb"]
"45345435" -> ["wertert","gfhjfgj"]

Answer 1

Updated Answer based on question update Ok, so you want the nth item from each value list as the values, which would look like this:

List<string> newDictKeys = new List<string>(new []{"12323","432234","45345435"});
List<string> listVal1 = new List<string>(new []{"dfgdfg","asdfds","wertert"});
List<string> listVal2 = new List<string>(new []{"ZCxzcx","xcvbcvb","gfhjfgj"});

List<List<string>> dictVals = new List<List<string>>();
dictVals.Add(listVal1);
dictVals.Add(listVal2);

Dictionary<string, List<string>> dict = 
    newDictKeys.Select((key, index) => new {key, index})
               .ToDictionary(entry => entry.key, 
                             entry => new List<string>(){dictVals[0][entry.index], dictVals[1][entry.index]});

Basically, it iterates through all the keys in newDictKeys , creates a temporary anonymous object with the key and the index of that key into the newDictKeys list (so {"12323", 0}, {"432234", 1}, ... ). Then, it creates a Dictionary where the key is the value from newDictKeys and for the value it gets the values from each sub-list in dictValues at the same index location.

Or, a simplified version (directly access the listVal1 and listVal2 collections instead of dictVals :

Dictionary<string, List<string>> dict = 
    newDictKeys.Select((key, index) => new {key, index})
               .ToDictionary(entry => entry.key, 
                             entry => new List<string>(){listVal1[entry.index], listVal2[entry.index]});

Original Answer If you want the same set of values for each entry in newDictKeys , you could map it like this:

List<string> newDictKeys = new List<string>(new []{"12323","432234","45345435"});
List<string> listVal1 = new List<string>(new []{"dfgdfg","asdfds","wertert"});
List<string> listVal2 = new List<string>(new []{"ZCxzcx","xcvbcvb","gfhjfgj"});

List<List<string>> dictVals = new List<List<string>>();
dictVals.Add(listVal1);
dictVals.Add(listVal2);

Dictionary<string, List<List<string>>> dict = 
    newDictKeys.ToDictionary(key => key, key => dictVals);

If you want a different set of values for each entry in newDictKeys , put the values into an array as well, so that they are in the same order as the keys, you could use .Select() to get the index of the key in the key list and then .ToDictionary() to map to the values you want, like this:

var valuesArray = new []{dictVals, dictVals2, ...};

Dictionary<string, List<List<string>>> dict = 
    newDictKeys.Select((key, index) => new {key, index})
               .ToDictionary(entry => entry.key, entry => valuesArray[entry.index]);

The valuesArray could also be a list, as long as it's values can be retrieved by an indexer.

Answer 2

Since You will have two lists stored for the same key why not to combine two lists together?

   List<string> newDictKeys  = new List<string>{ "12323", "432234", "45345435"};

    List<string> t = new List<string> { "dfgdfg", "asdfds", "wertert" };
    List<string> t2 = new List<string>{ "ZCxzcx", "xcvbcvb", "gfhjfgj" };
    t.AddRange(t2);

    Dictionary<string,List<string>> dict = newDictKeys.ToDictionary(key => key, key => t);

UPDATE

With the list of objects:

    List<string> newDictKeys = new List<string> { "12323", "432234", "45345435" };

    List<string> t = new List<string> { "dfgdfg", "asdfds", "wertert" };
    List<string> t2 = new List<string> { "ZCxzcx", "xcvbcvb", "gfhjfgj" };


    Dictionary<string, List<object>> dict = newDictKeys.ToDictionary(key => key, key => new List<object> {t, t2});

UPDATE 2 This should make a trick:

    List<string> newDictKeys = new List<string> { "12323", "432234", "45345435" };

    List<string> t = new List<string> { "dfgdfg", "asdfds", "wertert" };
    List<string> t2 = new List<string> { "ZCxzcx", "xcvbcvb", "gfhjfgj" };


    Dictionary<string, List<string>> dict = new Dictionary<string, List<string>>();

    foreach (var key in newDictKeys.Where(key => t.Count > 0 && t2.Count > 0))
    {
        dict.Add(key, new List<string> {t.FirstOrDefault(), t2.FirstOrDefault()});
        t.RemoveAt(0);
        t2.RemoveAt(0);
    }

UPDATE 3 With Queue

    List<string> newDictKeys = new List<string> { "12323", "432234", "45345435" };

    Queue<string> t = new Queue<string> (new []{ "dfgdfg", "asdfds", "wertert" });
    Queue<string> t2 = new Queue<string>(new[] { "ZCxzcx", "xcvbcvb", "gfhjfgj" });


    Dictionary<string, List<string>> dict = newDictKeys
    .Where(key => t.Count > 0 && t2.Count > 0)
    .ToDictionary(key => key, key => new List<string> {t.Dequeue(), t2.Dequeue()});