根据重复模式分割字串

Question

I have the following sting:

a='text1fig [1]text2fig [15]text3fig [234]text4fig [2234]text5' 

I want to split it to:

texts=['text1','text2','text3','text4','text5']

I tried:

import re    
texts=re.split('fig \\[[0-3000]\\]',texts) .  

but it doesn't work.
thank you

Answer 1

Number ranges don't work like that. Just use \\d instead. Additionally, you'll want a single backslash, as a double backslash is taken to be a literal backslash (you want it to escape the [ / ] metachars instead).

text = re.split(r'fig\s*\[\d+\]', a)

print(text)
['text1', 'text2', 'text3', 'text4', 'text5']

---

Regex Details

fig   
\s*   # 0 or more whitespace chars 
\[    # literal opening brace
\d+   # 1 or more digits
\]    # literal closing brace

Answer 2

You want to use "re.findall" instead of "re.split"

texts = re.findall('text\d', a)

['text1', 'text2', 'text3', 'text4', 'text5']