从 S3 存储桶中的文件夹中删除文件

Question

I have an AWS S3 bucket test-bucket with a data folder. The data folder will have multiple files.

I am able to delete the files in the S3 bucket. But what I want is to delete the files in the data folder without deleting the folder.

I tried the following:

aws s3 rm  s3://test-bucket/data/*

Also checked using --recursive option, but that does not work.

Is there a way I can delete the files in the folder using AWS CLI?

Answer 1

以下 aws cli 命令有效：

aws s3 rm s3://test-bucket --recursive --exclude="*" --include="data/*.*"

Answer 2

you can do it using aws cli : https://aws.amazon.com/cli/ and some unix command.

this aws cli commands should work:

aws s3 rm s3://<your_bucket_name> --exclude "*" --include "<your_regex>"

if you want to include sub-folders you should add the flag --recursive

or with unix commands:

aws s3 ls s3://<your_bucket_name>/ | awk '{print $4}' | xargs -I%  <your_os_shell>   -c 'aws s3 rm s3:// <your_bucket_name>/% $1'

explanation: list all files on the bucket --pipe--> get the 4th parameter(its the file name) --pipe--> run delete script with aws cli

Answer 3

aws s3 rm s3://bucket/folder1/folder2/ --recursive --dryrun

从我尝试时看到的情况来看，在末尾添加斜杠意味着在文件夹 2 下方删除，不包括文件夹 2。

Answer 4

We can remove all files including sub-folders as well from AWS-S3-BUCKET In Node.js by using the below function.

the same command can be used in AWS-CLI by configuring AWS in the command-line.

function removeAllFilesFromBucket(){
    const S3_REGION = "eu-west-1";
    const S3_BUCKET_NAME = "sample-staging";
    let filePathBucket = S3_BUCKET_NAME+'/assets/videos';

    let awsS3ShellCommand = 'aws s3 rm s3://'+filePathBucket+' --region '+S3_REGION+' --recursive';                 
    var { exec } = require('child_process');  
    exec(awsS3ShellCommand, (err, stdout, stderr) => {
        if (err) {
            console.log('err',err);                        
            return;
        }else{
            console.log('Bucket files and sub-folders Deleted successfully !!!'); 
            console.log(`stdout: ${stdout}`);
            console.log(`stderr: ${stderr}`); 
        }
    });  
}