在PHP MySQL中计算日期和时间以及回显

Question

I am trying to echo some text if the difference between datetime from MySQL and the current datetime is more than sixty seconds.

But my code is showing every time.

<?php
session_start();
require_once 'class.php';

$reg = new USER();

$stmt = $reg->runQuery("SELECT * FROM validation WHERE vid=2"); 
$stmt->execute(); 
$row = $stmt->fetch(PDO::FETCH_ASSOC);  
$usrmail = $row['vdate'];

$login_session_durations = 60;

if(((time() - $usrmail) > $login_session_durations)) { 
    echo "Ok";
}
?>

Date & Time set in MySQL is 2017-09-17 06:53:39.000000

Answer 1

time() gives you the output in Unix format like 1505622974 so to compare we need both the times variable in the same format.

<?php
    session_start();
    require_once 'class.php';

    $reg = new USER();

    $stmt = $reg->runQuery("SELECT * FROM validation WHERE vid=2"); 
    $stmt->execute(); 
    $row = $stmt->fetch(PDO::FETCH_ASSOC);  
    $usrmail = $row['vdate']; //The format for vdate: 2017-09-17 06:53:39.000000

    $login_session_durations = 60; //In Seconds

    if(((time() - strtotime($usrmail)) > $login_session_durations)) { 
        echo "Ok";
    }
?>