java字符串到日期时间的转换问题

Question

I can't seem to see the problem with the example code below. For some reason seems to be ignoring the year and saying the dates are the same, as can be seen in the output below. I must be missing something simple.

01/28/2006
01/16/2007
Tue Apr 01 00:00:00 PDT 2008
Tue Apr 01 00:00:00 PDT 2008
done

import java.util.*;
import java.text.DateFormat;
import java.text.ParseException;
import java.text.SimpleDateFormat;

    class ExampleProgram {
      public static void main(String[] args){
        DateFormat df = new SimpleDateFormat("dd/MM/yyyy");
        String d1String = "01/28/2006";
        String d2String = "01/16/2007";
        System.out.println(d1String);
        System.out.println(d2String);
        Date d1=null;
        try {
            d1 = df.parse(d1String);
        } catch (ParseException e) {                
            System.out.println(e.getMessage());
        }           
        Date d2=null;
        try {
            d2 = df.parse(d2String);
        } catch (ParseException e) {                
            System.out.println(e.getMessage());
        }
        System.out.println(d1);
        System.out.println(d2);
        System.out.println("done");
      }
    }

Answer 1

"dd/MM/yyyy"

应该读：

"MM/dd/yyyy"

Answer 2

正如彼得所提到的，字母的含义可以在这里的文档中找到： https : //docs.oracle.com/javase/1.5.0/docs/api/java/text/SimpleDateFormat.html 。

Answer 3

The reason that it wasn't giving you what you expected is like Peter said the SimpleDateFormat should read "MM/dd/yyyy"

The reason that the result is saying that they appear to be equal is because with the format that you've given it "dd/MM/yyyy" , d1String 's Month is 28. It is taking 28 - 12, adding a year, 16 - 12, adding another year, and the result is 4 (April) and the year is now 2008. Same thing for d2String .

Answer 4

您可以尝试将日期声明为Date对象。